CHEMICAL KINETICS

From baking a cake to determining the useful lifespan of a bridge, rates of chemical reactions play important roles in our understanding of processes that involve chemical changes. Two questions are typically posed when planning to carry out a chemical reaction. The first is: “Will the reaction produce the desired products in useful quantities?” The second question is: “How rapidly will the reaction occur?” A third question is often asked when investigating reactions in greater detail: “What specific molecular-level processes take place as the reaction occurs?” Knowing the answer to this question is of practical importance when the yield or rate of a reaction needs to be controlled.

The study of chemical kinetics concerns the second and third questions—that is, the rate at which a reaction yields products and the molecular-scale means by which a reaction occurs

Chemical Reaction Rates

A rate is a measure of how some property varies with time. Speed is a familiar rate that expresses the distance traveled by an object in a given amount of time. Wage is a rate that represents the amount of money earned by a person working for a given amount of time. Likewise, the rate of a chemical reaction is a measure of how much reactant is consumed, or how much product is produced, by the reaction in a given amount of time.

The rate of reaction is the change in the amount of a reactant or product per unit time. Reaction rates are therefore determined by measuring the time dependence of some property that can be related to reactant or product amounts. Rates of reactions that consume or produce gaseous substances, for example, are conveniently determined by measuring changes in volume or pressure. For reactions involving one or more colored substances, rates may be monitored via measurements of light absorption. For reactions involving aqueous electrolytes, rates may be measured via changes in a solution’s conductivity

For reactants and products in solution, their relative amounts (concentrations) are conveniently used for purposes of expressing reaction rates. For example, the concentration of hydrogen peroxide, H2O2, in an aqueous solution changes slowly over time as it decomposes according to the equation

2H2O2 (aq) ———> 2H2O (l) + O2 (g)

The rate at which the hydrogen peroxide decomposes can be expressed in terms of the rate of change of its concentration, as shown here

This mathematical representation of the change in species concentration over time is the rate expression for the reaction. The brackets indicate molar concentrations, and the symbol delta (Δ) indicates “change in.” Thus [H2 O2]t1 represents the molar concentration of hydrogen peroxide at some time t1; likewise [H2 O2]t2  represents the molar concentration of hydrogen peroxide at some time t2 and Δ[H2O2] represents the change  in molar concentration of hydrogen peroxide during the time interval Δt (that is, t2t1). Since the reactant concentration decreases as the reaction proceeds, Δ[H2O2] is a negative quantity. Reaction rates are, by convention, positive quantities, and so this negative change in concentration is multiplied by −1. The table below provides an example of data collected during the decomposition of H2O2.

The rate of decomposition of H2O2 in an aqueous solution decreases as the concentration of H2O2  decreases.

To obtain the tabulated results for this decomposition, the concentration of hydrogen peroxide was measured every 6 hours over the course of a day at a constant temperature of 40 °C. Reaction rates were computed for each time interval by dividing the change in concentration by the corresponding time increment, as shown here for the first 6-hour period

This behavior indicates the reaction continually slows with time. Using the concentrations at the beginning and end of a time period over which the reaction rate is changing results in the calculation of an average rate for the reaction over this time interval. At any specific time, the rate at which a reaction is proceeding is known as its instantaneous rate. The instantaneous rate of a reaction at “time zero,” when the reaction commences, is its initial rate. Consider the analogy of a car slowing down as it approaches a stop sign. The vehicle’s initial rate—analogous to the beginning of a chemical reaction—would be the speedometer reading at the moment the driver begins pressing the brakes (t0). A few moments later, the instantaneous rate at a specific moment—call it t1—would be somewhat slower, as indicated by the speedometer reading at that point in time. As time passes, the instantaneous rate will continue to fall until it reaches zero, when the car (or reaction) stops. Unlike instantaneous speed, the car’s average speed is not indicated by the speedometer; but it can be calculated as the ratio of the distance traveled to the time required to bring the vehicle to a complete stop (Δt). Like the decelerating car, the average rate of a chemical reaction will fall somewhere between its initial and final rates.

The instantaneous rate of a reaction may be determined one of two ways. If experimental conditions permit the measurement of concentration changes over very short time intervals, then average rates computed as described earlier provide reasonably good approximations of instantaneous rates. Alternatively, a graphical procedure may be used that, in effect, yields the results that would be obtained if short time interval measurements were possible. In a plot of the concentration of hydrogen peroxide against time, the instantaneous rate of decomposition of H2O2 at any time t is given by the slope of a straight line that is tangent  to the curve at that time (Below Graph). These tangent line slopes may be evaluated using calculus

This graph shows a plot of concentration versus time for a 1.000 M solution of H2O2. The rate at any time is equal to the negative of the slope of a line tangent to the curve at that time. Tangents are shown at t = 0 h (“initial rate”) and at t = 12 h (“instantaneous rate” at 12 h)

Relative Rates of Reaction

The rate of a reaction may be expressed as the change in concentration of any reactant or product. For any given reaction, these rate expressions are all related simply to one another according to the reaction stoichiometry. The rate of the general reaction

aA —-à bB

can be expressed in terms of the decrease in the concentration of A or the increase in the concentration of B. These two rate expressions are related by the stoichiometry of the reaction:

Consider the reaction represented by the following equation:

2NH3 (g) —–à N2 (g) + 3 H2 (g)

The relation between the reaction rates expressed in terms of nitrogen production and ammonia consumption, for example, is:

Note that a negative sign has been included as a factor to account for the  opposite signs of the two amount changes (the reactant amount is decreasing while the product amount is increasing). For homogeneous reactions, both the reactants and products are present in the same solution and thus occupy the same volume, so the molar amounts may be replaced with molar concentrations

The below graph illustrates the change in concentrations over time for the decomposition of ammonia into nitrogen and hydrogen at 1100 °C. Slopes of the tangent lines at t = 500 s show that the instantaneous rates derived from all three species involved in the reaction are related by their stoichiometric factors. The rate of hydrogen production, for example, is observed to be three times greater than that for nitrogen production:

Changes in concentrations of the reactant and products for the reaction 2NH3 (g) —–à N2 (g) + 3 H2 (g)

 The  rates of change of the three concentrations are related by the reaction stoichiometry, as shown by the different slopes of the tangents at t = 500 s

Factors Affecting Reaction Rates

The rates at which reactants are consumed and products are formed during chemical reactions vary greatly. Five factors typically affecting the rates of chemical reactions will be explored in this section: the chemical nature of the reacting substances, the state of subdivision (one large lump versus many small particles) of the reactants, the temperature of the reactants, the concentration of the reactants, and the presence of a catalyst

The Chemical Nature of the Reacting Substances

The rate of a reaction depends on the nature of the participating substances. Reactions that appear similar may have different rates under the same conditions, depending on the identity of the reactants. For example, when small pieces of the metals iron and sodium are exposed to air, the sodium reacts completely with air overnight, whereas the iron is barely affected. The active metals calcium and sodium both react with water to form hydrogen gas and a base. Yet calcium reacts at a moderate rate, whereas sodium reacts so rapidly that the reaction is almost explosive

The Physical States of the Reactants

A chemical reaction between two or more substances requires intimate contact between the reactants. When reactants are in different physical states, or phases (solid, liquid, gaseous, dissolved), the reaction takes place only at the interface between the phases. Consider the heterogeneous reaction between a solid phase and either a liquid or gaseous phase. Compared with the reaction rate for large solid particles, the rate for smaller particles will be greater because the surface area in contact with the other reactant phase is greater. For example, large pieces of iron react more slowly with acids than they do with finely divided iron powder (Figure below ). Large pieces of wood smolder, smaller pieces burn rapidly, and saw dust burns explosively

(a) Iron powder reacts rapidly with dilute hydrochloric acid and produces bubbles of hydrogen gas: 2Fe(s) + 6HCl(aq) ———à 2FeCl3(aq) + 3H2(g). (b) An iron nail reacts more slowly because the surface area exposed to the acid is much less.

Temperature of the Reactants

Chemical reactions typically occur faster at higher temperatures. Food can spoil quickly when left on the kitchen counter. However, the lower temperature inside of a refrigerator slows that process so that the same food remains fresh for days. Gas burners, hot plates, and ovens are often used in the laboratory to increase the speed of reactions that proceed slowly at ordinary temperatures. For many chemical processes, reaction rates are approximately doubled when the temperature is raised by 10 °C.

Concentrations of the Reactants

The rates of many reactions depend on the concentrations of the reactants. Rates usually increase when the concentration of one or more of the reactants increases. For example, calcium carbonate (CaCO3) deteriorates as a result of its reaction with the pollutant sulfur dioxide. The rate of this reaction depends on the amount of sulfur dioxide in the air (Figure 17.7). An acidic oxide, sulfur dioxide combines with water vapor in the air to produce sulfurous acid in the following reaction :

In a polluted atmosphere where the concentration of sulfur dioxide is high, calcium carbonate deteriorates more rapidly than in less polluted air. Similarly, phosphorus burns much more rapidly in an atmosphere of pure oxygen than in air, which is only about 20% oxygen

Statues made from carbonate compounds such as limestone and marble typically weather slowly over time due to the actions of water, and thermal expansion and contraction. However, pollutants like sulfur dioxide can accelerate weathering. As the concentration of air pollutants increases, deterioration of limestone occurs more rapidly. (credit: James P Fisher III)

The Presence of a Catalyst

Relatively dilute aqueous solutions of hydrogen peroxide, H2O2, are commonly used as topical antiseptics. Hydrogen peroxide decomposes to yield water and oxygen gas according to the equation :

2 H2 O2 —-à 2 H2O (l) + O2 (g)

Under typical conditions, this decomposition occurs very slowly. When dilute H2O2(aq) is poured onto an open wound, however, the reaction occurs rapidly and the solution foams because of the vigorous production of oxygen gas. This dramatic difference is caused by the presence of substances within the wound’s exposed tissues that accelerate the decomposition process. Substances that function to increase the rate of a reaction are called catalysts .

Rate Laws

The rate of a reaction is often affected by the concentrations of reactants.  Rate laws (sometimes called differential rate laws) or rate equations are mathematical expressions that describe the relationship between the rate of a chemical reaction and the concentration of its reactants. As an example, consider the reaction described by the chemical equation

aA + bB ———- Products

where a and b are stoichiometric coefficients. The rate law for this reaction is written as:

 rate = k [ A ] m [ B ]

in which [A] and [B] represent the molar concentrations of reactants, and k is the rate constant, which is specific for a particular reaction at a particular temperature. The exponents m and n are the reaction orders and are typically positive integers, though they can be fractions, negative, or zero. The rate constant k and the reaction orders m and n must be determined experimentally by observing how the rate of a reaction changes as the concentrations of the reactants are changed. The rate constant k is independent of the reactant concentrations, but it does vary with temperature.

The reaction orders in a rate law describe the mathematical dependence of the rate on reactant concentrations. Referring to the generic rate law above, the reaction is m order with respect to A and n order with respect to B. For example, if m = 1 and n = 2, the reaction is first order in A and second order in B. The overall reaction order is simply the sum of orders for each reactant. For the example rate law here, the reaction is third order overall (1 + 2 = 3). A few specific examples are shown below to further illustrate this concept.

The rate law:

rate=k[H2O2]
describes a reaction that is first order in hydrogen peroxide and first order overall. The rate law:

rate=k[C4H6]2
describes a reaction that is second order in C4H6 and second order overall. The rate law:

rate=k[H+][OH]
describes a reaction that is first order in H+, first order in OH, and second order overall.

Reaction Order and Rate Constant Units

In some cases , the reaction orders in the rate law happen to be the same as the coefficients in the chemical equation for the reaction. This is merely a coincidence and very often not the case

Rate laws may exhibit fractional orders for some reactants, and negative reaction orders are sometimes observed when an increase in the concentration of one reactant causes a decrease in reaction rate. A few examples illustrating these points are provided

It is important to note that rate laws are determined by experiment only and are not reliably predicted by reaction stoichiometry

Note that the units in this table were derived using specific units for concentration (mol/L) and time (s), though any valid units for these two properties may be used.

Integrated Rate Laws

The rate laws discussed thus far relate the rate and the concentrations of reactants. We can also determine a second form of each rate law that relates the concentrations of reactants and time. These are called integrated rate laws. We can use an integrated rate law to determine the amount of reactant or product present after a period of time or to estimate the time required for a reaction to proceed to a certain extent. For example, an integrated rate law is used to determine the length of time a radioactive material must be stored for its radioactivity to decay to a safe level.

Using calculus, the differential rate law for a chemical reaction can be integrated with respect to time to give an equation that relates the amount of reactant or product present in a reaction mixture to the elapsed time of the reaction. This process can either be very straightforward or very complex, depending on the complexity of the differential rate law. For purposes of discussion, we will focus on the resulting integrated rate laws for first-

, second-, and zero-order reactions

First-Order Reactions

Integration of the rate law for a simple first-order reaction (rate = k[A]) results in an equation describing how the reactant concentration varies with time

[A]t = [A]0 e-kt

where [A]t is the concentration of A at any time t, [A]0 is the initial concentration of A, and k is the first-order  rate constant

For mathematical convenience, this equation may be rearranged to other formats, including direct and indirect proportionalities :

Second-Order Reactions

The equations that relate the concentrations of reactants and the rate constant of second-order reactions can be fairly complicated. To illustrate the point with minimal complexity, only the simplest second-order reactions will be described here, namely, those whose rates depend on the concentration of just one reactant. For these types of reactions, the differential rate law is written as:

rate = k [A]2

The integrated rate law for second-order reactions has the form of the equation of a straight line:

Zero-Order Reactions

For zero-order reactions, the differential rate law is:

                        rate = k

A zero-order reaction thus exhibits a constant reaction rate, regardless of the concentration of its reactant(s). This may seem counterintuitive, since the reaction rate certainly can’t be finite when the reactant concentration is zero. For purposes of this introductory text, it will suffice to note that zero-order kinetics are observed for some reactions only under certain specific conditions. These same reactions exhibit different kinetic behaviors when the specific conditions aren’t met, and for this reason the more prudent term pseudozero-order is sometimes used. The integrated rate law for a zero-order reaction is a linear function:

[A]t = -kt = [A]0

y = mx + b

A plot of [A] versus t for a zero-order reaction is a straight line with a slope of −k and a y-intercept of [A]0. Below graph  shows a plot of [NH3] versus t for the thermal decomposition of ammonia at the surface of two different heated solids. The decomposition reaction exhibits first-order behavior at a quartz (SiO2) surface, as suggested by the exponentially decaying plot of concentration versus time. On a tungsten surface, however, the plot is linear, indicating zero-order kinetics.

The decomposition of NH3 on a tungsten (W) surface is a zero-order reaction, whereas on a quartz (SiO2) surface, the reaction is first order

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Basic Concepts of Chemistry – II

Atomic Structure and Symbolism

The development of modern atomic theory revealed much about the inner structure of atoms. It was learned that an atom contains a very small nucleus composed of positively charged protons and uncharged neutrons, surrounded by a much larger volume of space containing negatively charged electrons. The nucleus contains the majority of an atom’s mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom’s volume. The diameter of an atom is on the order of 10−10 m, whereas the diameter of the nucleus is roughly 10−15 m—about 100,000 times smaller. For a perspective about their relative sizes, consider this: If the nucleus were the size of a blueberry, the atom would be about the size of a football stadium

Atoms—and the protons, neutrons, and electrons that compose them—are extremely small. For example, a carbon atom weighs less than 2 X 10-23 g ,  and an electron has a charge of less than 2 X 10-19 C (coulomb). When describing the properties of tiny objects such as atoms, we use appropriately small units of measure, such as the atomic mass unit (amu) and the fundamental unit of charge (e). The amu was originally defined based on hydrogen, the lightest element, then later in terms of oxygen. Since 1961, it has been defined with regard to the most abundant isotope of carbon, atoms of which are assigned masses of exactly 12 amu. (This isotope is known as “carbon-12” as will be discussed later in this module.) Thus, one amu is exactly of the mass of one carbon-12 atom ie 1 amu = 1.6605 X 10-24 g . (The Dalton (Da) and the unified atomic mass unit (u) are alternative units that are equivalent to the amu.) The fundamental unit of charge (also called the elementary charge) equals the magnitude of the charge of an electron (e) with e = 1.602 X 10-19 Coulomb

A proton has a mass of 1.0073 amu and a charge of 1+. A neutron is a slightly heavier particle with a mass 1.0087 amu and a charge of zero; as its name suggests, it is neutral. The electron has a charge of 1− and is a much lighter particle with a mass of about 0.00055 amu (it would take about 1800 electrons to equal the mass of one proton). The properties of these fundamental particles are summarized in the below table . ( You might notice that the sum of an atom’s subatomic particles does not equal the atom’s actual mass: The total mass of six protons, six neutrons, and six electrons is 12.0993 amu, slightly larger than 12.00 amu. This “missing” mass is known as the mass defect, and you will learn about it in  nuclear chemistry.)

Properties of Subatomic Particles

Name Location Charge (C) Unit Charge Mass (amu) Mass (g)
electron outside nucleus −1.602 10−19 1− 0.00055 0.00091 10−24
proton nucleus 1.602 10−19 1+ 1.00727 1.67262 10−24
neutron nucleus 0 0 1.00866 1.67493 10−24

The number of protons in the nucleus of an atom is its atomic number (Z). This is the defining trait of an element: Its value determines the identity of the atom. For example, any atom that contains six protons is the element carbon and has the atomic number 6, regardless of how many neutrons or electrons it may have. A neutral atom must contain the same number of positive and negative charges, so the number of protons equals the number of electrons. Therefore, the atomic number also indicates the number of electrons in an atom. The total number of protons and neutrons in an atom is called its mass number (A). The number of neutrons is therefore the difference between the mass number and the atomic number:

Mass Number (A) = Number of Protons + Number of Neutrons

A – Z = Number of Neutrons

Atoms are electrically neutral if they contain the same number of positively charged protons and negatively charged electrons. When the numbers of these subatomic particles are not equal, the atom is electrically charged and is called an ion. The charge of an atom is defined as follows:

Atomic charge = number of protons − number of electrons

Atoms (and molecules) typically acquire charge by gaining or losing electrons. An atom that gains one or more electrons will exhibit a negative charge and is called an anion. Positively charged atoms called cations are formed when an atom loses one or more electrons. For example, a neutral sodium atom (Z = 11) has 11 electrons. If this atom loses one electron, it will become a cation with a 1+ charge (11 − 10 = 1+). A neutral oxygen atom (Z = 8) has eight electrons, and if it gains two electrons it will become an anion with a 2− charge (8 − 10 = 2−).

Chemical Symbols

A chemical symbol is an abbreviation that we use to indicate an element or an atom of an element. For example, the symbol for mercury is Hg (Figure 2.13). We use the same symbol to indicate one atom of mercury (microscopic domain) or to label a container of many atoms of the element mercury (macroscopic domain).

The symbol Hg represents the element mercury regardless of the amount; it could represent one  atom of mercury or a large amount of mercury

The symbols for several common elements and their atoms are listed in the below table . Some symbols are derived from the common name of the element; others are abbreviations of the name in another language. Most symbols have one or two letters, but three-letter symbols have been used to describe some elements that have atomic numbers greater than 112. To avoid confusion with other notations, only the first letter of a symbol is capitalized. For example, Co is the symbol for the element cobalt, but CO is the notation for the compound carbon monoxide, which contains atoms of the elements carbon (C) and oxygen (O). All known elements and their symbols are in the periodic table .

Some Common Elements and Their Symbols

Element  Symbol Element Symbol
aluminum Al iron Fe (from ferrum)
bromine Br lead Pb (from plumbum)
calcium Ca magnesium Mg
carbon C mercury Hg (from hydrargyrum)
chlorine Cl nitrogen N
chromium Cr oxygen O
cobalt Co potassium K (from kalium)
copper Cu (from cuprum) silicon Si
fluorine F silver Ag (from argentum)
gold Au (from aurum) sodium Na (from natrium)
helium He sulfur S
hydrogen H tin Sn (from stannum)
iodine I zinc Zn

Traditionally, the discoverer (or discoverers) of a new element names the element. However, until the name is recognized by the International Union of Pure and Applied Chemistry (IUPAC), the recommended name of the new element is based on the Latin word(s) for its atomic number. For example, element 106 was called unnilhexium (Unh), element 107 was called unnilseptium (Uns), and element 108 was called unniloctium (Uno) for several years. These elements are now named after scientists (or occasionally locations); for example, element 106 is now known as seaborgium (Sg) in honor of Glenn Seaborg, a Nobel Prize winner who was active in the discovery of several heavy elements. Element 109 was named in honor of Lise Meitner, who discovered nuclear fission, a phenomenon that would have world-changing impacts; Meitner also contributed to the discovery of some major isotopes, discussed immediately below

Isotopes

The symbol for a specific isotope of any element is written by placing the mass number as a superscript (above the letter) to the left of the element symbol . The atomic number is sometimes written as a subscript (below the letter)  preceding the symbol, but since this number defines the element’s identity, as does its symbol, it is often omitted. For example, magnesium exists as a mixture of three isotopes, each with an atomic number of 12 and with mass numbers of 24, 25, and 26, respectively. These isotopes can be identified as 24Mg, 25Mg, and 26Mg. These isotope symbols are read as “element, mass number” and can be symbolized consistent with this reading. For instance, 24Mg is read as “magnesium 24,” and can be written as “magnesium-24” or “Mg-24.” 25Mg is read as “magnesium 25,” and can be written as “magnesium-25” or “Mg-25.” All magnesium atoms have 12 protons in their nucleus. They differ only because a 24Mg atom has 12 neutrons in its nucleus, a 25Mg atom has 13 neutrons, and a 26Mg has 14 neutrons

The symbol for an atom indicates the element via its usual two-letter symbol, the mass number as a left superscript, the atomic number as a left subscript (sometimes omitted), and the charge as a right superscript

Information about the naturally occurring isotopes of elements with atomic numbers 1 through 10 is given in the below table . Note that in addition to standard names and symbols, the isotopes of hydrogen are often referred to using common names and accompanying symbols. Hydrogen-2, symbolized 2H, is also called deuterium and sometimes symbolized D. Hydrogen-3, symbolized 3H, is also called tritium and sometimes symbolized T

Nuclear Compositions of Atoms of the Very Light Elements

Element Symbol  Atomic Number Number of Protons Number of Neutrons Mass (amu) % Natural Abundance
        hydrogen   (protium)   1   1   0   1.0078   99.989
  (deuterium)   1   1   1   2.0141   0.0115
  (tritium)   1   1   2   3.01605   — (trace)
  helium   2 2 1 3.01603 0.00013
  2 2 2 4.0026 100
  lithium   3 3 3 6.0151 7.59
  3 3 4 7.0160 92.41
beryllium   4 4 5 9.0122 100
  boron   5 5 5 10.0129 19.9
  5 5 6 11.0093 80.1
    carbon   6 6 6 12.0000 98.89
  6 6 7 13.0034 1.11
  6 6 8 14.0032 — (trace)
  nitrogen   7 7 7 14.0031 99.63
  7 7 8 15.0001 0.37
    oxygen   8 8 8 15.9949 99.757
  8 8 9 16.9991 0.038
  8 8 10 17.9992 0.205
fluorine   9 9 10 18.9984 100
neon   10 10 10 19.9924 90.48

Atomic Mass

Because each proton and each neutron contribute approximately one amu to the mass of an atom, and each electron contributes far less, the atomic mass of a single atom is approximately equal to its mass number (a whole number). However, the average masses of atoms of most elements are not whole numbers because most elements exist naturally as mixtures of two or more isotopes.

The mass of an element shown in a periodic table or listed in a table of atomic masses is a weighted, average mass of all the isotopes present in a naturally occurring sample of that element. This is equal to the sum of each individual isotope’s mass multiplied by its fractional abundance

For example, the element boron is composed of two isotopes: About 19.9% of all boron atoms are 10B with a mass of 10.0129 amu, and the remaining 80.1% are 11B with a mass of 11.0093 amu. The average atomic mass for boron is calculated to be:

Boron Average Mass =  (0.199 X 10.0129 amu) + (0.801 X 11.0093 amu)
= 11.99 amu + 8.82 amu
= 10.81 amu

It is important to understand that no single boron atom weighs exactly 10.8 amu; 10.8 amu is the average mass of all boron atoms, and individual boron atoms weigh either approximately 10 amu or 11 amu.

Chemical Formulas

A molecular formula is a representation of a molecule that uses chemical symbols to indicate the types of atoms followed by subscripts to show the number of atoms of each type in the molecule. (A subscript is used only when more than one atom of a given type is present.) Molecular formulas are also used as abbreviations for the names of compounds

The structural formula for a compound gives the same information as its molecular formula (the types and numbers of atoms in the molecule) but also shows how the atoms are connected in the molecule. The structural formula for methane contains symbols for one C atom and four H atoms, indicating the number of atoms in the molecule  (Below figure) . The lines represent bonds that hold the atoms together. (A chemical bond  is an attraction between atoms or ions that holds them together in a molecule or a crystal.  For now, simply know that the lines are an indication of how the atoms are connected in a molecule. A ball-and-stick model shows the geometric arrangement of the atoms with atomic sizes not to scale, and a space-filling model shows the relative sizes of the atoms

A methane molecule can be represented as (a) a molecular formula, (b) a structural formula, (c) a ball-and-stick model, and (d) a space-filling model. Carbon and hydrogen atoms are represented by black and white spheres, respectively

Although many elements consist of discrete, individual atoms, some exist as molecules made up of two or more atoms of the element chemically bonded together. For example, most samples of the elements hydrogen, oxygen, and nitrogen are composed of molecules that contain two atoms each (called diatomic molecules) and thus have the molecular formulas H2, O2, and N2, respectively. Other elements commonly found as diatomic molecules are fluorine (F2), chlorine (Cl2), bromine (Br2), and iodine (I2). The most common form of the element sulfur is composed of molecules that consist of eight atoms of sulfur; its molecular formula is S8

A molecule of sulfur is composed of eight sulfur atoms and is therefore written as S8. It can be represented as (a) a structural formula, (b) a ball-and-stick model, and (c) a space-filling model. Sulfur atoms are represented by yellow spheres

It is important to note that a subscript following a symbol and a number in front of a symbol do not represent the same thing; for example, H2 and 2H represent distinctly different species. H2 is a molecular formula; it represents a diatomic molecule of hydrogen, consisting of two atoms of the element that are chemically bonded together. The expression 2H, on the other hand, indicates two separate hydrogen atoms that are not combined as a unit. The expression 2H2 represents two molecules of diatomic hydrogen

The symbols H, 2H, H2, and 2H2 represent very different entities

Compounds are formed when two or more elements chemically combine, resulting in the formation of bonds. For example, hydrogen and oxygen can react to form water, and sodium and chlorine can react to form table salt. We sometimes describe the composition of these compounds with an empirical formula, which indicates the types of atoms present and the simplest whole-number ratio of the number of atoms (or ions) in the compound. For example, titanium dioxide (used as pigment in white paint and in the thick, white, blocking type of sunscreen) has an empirical formula of TiO2. This identifies the elements titanium (Ti) and oxygen (O) as the constituents of titanium dioxide, and indicates the presence of twice as many atoms of the element oxygen as atoms of the element titanium

The white compound titanium dioxide provides effective protection from the sun. (b) A crystal of titanium dioxide, TiO2, contains titanium and oxygen in a ratio of 1 to 2. The titanium atoms are gray and the oxygen atoms are red. (credit a: modification of work by “osseous”/Flickr)

As discussed previously, we can describe a compound with a molecular formula, in which the subscripts indicate the actual numbers of atoms of each element in a molecule of the compound. In many cases, the molecular formula of a substance is derived from experimental determination of both its empirical formula and its molecular mass (the sum of atomic masses for all atoms composing the molecule). For example, it can be determined experimentally that benzene contains two elements, carbon (C) and hydrogen (H), and that for every carbon atom in benzene, there is one hydrogen atom. Thus, the empirical formula is CH. An experimental determination of the molecular mass reveals that a molecule of benzene contains six carbon atoms and six hydrogen atoms, so the molecular formula for benzene is C6H6

Benzene, C6H6, is produced during oil refining and has many industrial uses. A benzene molecule can be represented as (a) a structural formula, (b) a ball-and-stick model, and (c) a space-filling model. (d) Benzene is a clear liquid. (credit d: modification of work by Sahar Atwa)

For example, the molecular formula for acetic acid, the component that gives vinegar its sharp taste, is C2H4O2. This formula indicates that a molecule of acetic acid  (Below Figure) contains two carbon atoms, four hydrogen atoms, and two oxygen atoms. The ratio of atoms is 2:4:2. Dividing by the lowest common denominator (2) gives the simplest, whole-number ratio of atoms, 1:2:1, so the empirical formula is CH2O. Note that a molecular formula is always a whole- number multiple of an empirical formula.

  • Vinegar contains acetic acid, C2H4O2, which has an empirical formula of CH2O. It can be represented as (b) a structural formula and (c) as a ball-and-stick model. (credit a: modification of work by “HomeSpot HQ”/Flickr)

It is important to be aware that it may be possible for the same atoms to be arranged in different ways: Compounds with the same molecular formula may have different atom-to-atom bonding and therefore different structures. For example, could there be another compound with the same formula as acetic acid, C2H4O2? And if so, what would be the structure of its molecules?

Two C atoms, four H atoms, and two O atoms can also be arranged to form a methyl formate, which is used in manufacturing, as an insecticide, and for quick-drying finishes. Methyl formate molecules have one of the oxygen atoms between the two carbon atoms, differing from the arrangement in acetic acid molecules. Acetic acid and methyl formate are examples of isomers—compounds with the same chemical formula but different molecular structures (Below Figure) . Note that this small difference in the arrangement of the atoms has a major effect on their respective chemical properties. You would certainly not want to use a solution of methyl formate as a substitute for a solution of acetic acid (vinegar) when you make salad dressing.

Molecules of (a) acetic acid and methyl formate (b) are structural isomers; they have the same formula (C2H4O2) but different structures (and therefore different chemical properties).

Formula Mass and the Mole Concept

Many argue that modern chemical science began when scientists started exploring the quantitative as well as the qualitative aspects of chemistry. For example, Dalton’s atomic theory was an attempt to explain the results of measurements that allowed him to calculate the relative masses of elements combined in various compounds. Understanding the relationship between the masses of atoms and the chemical formulas of compounds allows us to quantitatively describe the composition of substances.

Formula Mass

We have seen the development of the atomic mass unit, the concept of average atomic masses, and the use of chemical formulas to represent the elemental makeup of substances. These ideas can be extended to calculate the formula mass of a substance by summing the average atomic masses of  all the atoms represented in the substance’s formula.

Formula Mass for Covalent Substances

For covalent substances, the formula represents the numbers and types of atoms composing a single molecule of the substance; therefore, the formula mass may be correctly referred to as a molecular mass. Consider chloroform (CHCl3), a covalent compound once used as a surgical anesthetic and now primarily used in the production of tetrafluoroethylene, the building block for the “anti-stick” polymer, Teflon. The molecular formula of chloroform indicates that a single molecule contains one carbon atom, one hydrogen atom, and three chlorine atoms. The average molecular mass of a chloroform molecule is therefore equal to the sum of the average atomic masses of these atoms. Below figure outlines the calculations used to derive the molecular mass of chloroform, which is 119.37 amu

The average mass of a chloroform molecule, CHCl3, is 119.37 amu, which is the sum of the average atomic masses of each of its constituent atoms. The model shows the molecular structure of chloroform

Likewise, the molecular mass of an aspirin molecule, C9H8O4, is the sum of the atomic masses of nine carbon atoms, eight hydrogen atoms, and four oxygen atoms, which amounts to 180.15 amu

The average mass of an aspirin molecule is 180.15 amu. The model shows the molecular structure of aspirin, C9H8O4

Formula Mass for Ionic Compounds

Ionic compounds are composed of discrete cations and anions combined in ratios to yield electrically neutral bulk matter. The formula mass for an ionic compound is calculated in the same way as the formula mass for covalent compounds: by summing the average atomic masses of all the atoms in the compound’s formula. Keep in mind, however, that the formula for an ionic compound does not represent the composition of a  discrete molecule, so it may not correctly be referred to as the “molecular mass.”

As an example, consider sodium chloride, NaCl, the chemical name for common table salt. Sodium chloride is an ionic compound composed of sodium cations, Na+, and chloride anions, Cl−, combined in a 1:1 ratio. The formula mass for this compound is computed as 58.44 amu

Table salt, NaCl, contains an array of sodium and chloride ions combined in a 1:1 ratio. Its formula mass is 58.44 amu

Note that the average masses of neutral sodium and chlorine atoms were used in this computation, rather than   the masses for sodium cations and chlorine anions. This approach is perfectly acceptable when computing the formula mass of an ionic compound. Even though a sodium cation has a slightly smaller mass than a sodium atom (since it is missing an electron), this difference will be offset by the fact that a chloride anion is slightly more massive than a chloride atom (due to the extra electron). Moreover, the mass of an electron is negligibly small with respect to the mass of a typical atom. Even when calculating the mass of an isolated ion, the missing or additional electrons can generally be ignored, since their contribution to the overall mass is negligible, reflected only in the nonsignificant digits that will be lost when the computed mass is properly rounded. The few exceptions to this guideline are very light ions derived from elements with precisely known atomic masses.

The Mole Concept and Molar Mass

The identity of a substance is defined not only by the types of atoms or ions it contains, but by the quantity of each type of atom or ion. For example, water, H2O, and hydrogen peroxide, H2O2, are alike in that their respective molecules are composed of hydrogen and oxygen atoms. However, because a hydrogen peroxide molecule contains two oxygen atoms, as opposed to the water molecule, which has only one, the two substances exhibit very different properties. Today, sophisticated instruments allow the direct measurement of these defining microscopic traits; however, the same traits were originally derived from the measurement of macroscopic properties (the masses and volumes of bulk quantities of matter) using relatively simple tools (balances and volumetric glassware). This experimental approach required the introduction of a new unit for amount of substances, the mole, which remains indispensable in modern chemical science.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a sample of matter. One Latin connotation for the word “mole” is “large mass” or “bulk,” which is consistent with its use as the name for this unit. The mole provides a link between an easily measured macroscopic property, bulk mass, and an  extremely  important  fundamental  property, number of atoms, molecules, and so forth. A mole of substance is that amount in which there are 6.02214076 X 1023 discrete entities (atoms or molecules). This large number is a fundamental constant known as Avogadro’s number (NA) or the Avogadro constant in honor of Italian scientist Amedeo Avogadro. This constant is properly reported with an explicit unit of “per mole,” a conveniently rounded version being 6.022 X 1023 / mol

Consistent with its definition as an amount unit, 1 mole of any element contains the same number of atoms as 1 mole of any other element. The masses of 1 mole of different elements, however, are different, since the masses of the individual atoms are drastically different. The molar mass of an element (or compound) is the mass in grams of 1 mole of that substance, a property expressed in units of grams per mole (g/mol)

Each sample contains 6.022 X 10 23  atoms —1.00 mol of atoms. From left to right (top row): 65.4 g zinc, 12.0 g carbon, 24.3 g magnesium, and 63.5 g copper. From left to right (bottom row): 32.1 g sulfur, 28.1 g silicon, 207 g lead, and 118.7 g tin. (credit: modification of work by Mark Ott)

The molar mass of any substance is numerically equivalent to its atomic or formula weight in amu. Per the amu definition, a single 12C atom weighs 12 amu (its atomic mass is 12 amu). A mole of 12C weighs 12 g (its molar mass is 12 g/mol). This relationship holds for all elements, since their atomic masses are measured relative to that of the amu-reference substance, 12C. Extending this principle, the molar mass of a compound in   grams is likewise numerically equivalent to its formula mass in amu

Each sample contains 6.02 X 1023  molecules or formula units—1.00 mol of the compound or element. Clock-wise from the upper left: 130.2 g of C8H17OH (1-octanol, formula mass 130.2 amu), 454.4 g of HgI2 (mercury(II) iodide, formula mass 454.4 amu), 32.0 g of CH3OH (methanol, formula mass 32.0 amu) and 256.5 g of S8 (sulfur, formula mass 256.5 amu). (credit: Sahar Atwa)

While atomic mass and molar mass are numerically equivalent, keep in mind that they are vastly different in terms of scale, as represented by the vast difference in the magnitudes of their respective units (amu versus g). To appreciate the enormity of the mole, consider a small drop of water weighing about 0.03 g . Although this represents just a tiny fraction of 1 mole of water (~18 g), it contains more water molecules than can be clearly imagined. If the molecules were distributed equally among the roughly seven billion people on earth, each person would receive more than 100 billion molecules.

Determining Empirical and Molecular Formulas

The previous section discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, one may determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, these same principles will be applied to derive the chemical formulas of unknown substances from experimental mass measurements

Percent Composition

The elemental makeup of a compound defines its chemical identity, and chemical formulas are the most succinct way of representing this elemental makeup. When a compound’s formula is unknown, measuring the mass of each of its constituent elements is often the first step in the process of determining the formula experimentally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound.

For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows :

% H = ( Mass H / Mass Compound ) X 100%

% C = ( Mass C / Mass Compound ) X 100%

If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:

% H = (0.25 g / 10 g ) X 100% = 25%

% C = (0.75 g / 10 g ) X 100% = 75%

Determining Percent Composition from Molecular or Empirical Formulas

Percent composition is also useful for evaluating the relative abundance of a given element in different compounds of known formulas. As one example, consider the common nitrogen-containing fertilizers ammonia (NH3), ammonium nitrate (NH4NO3), and urea (CH4N2O). The element nitrogen is the active ingredient for agricultural purposes, so the mass percentage of nitrogen in the compound is a practical and economic concern for consumers choosing among these fertilizers. For these sorts of applications, the percent composition of a compound is easily derived from its formula mass and the atomic masses of its constituent elements. A molecule of NH3 contains one N atom weighing 14.01 amu and three H atoms weighing a total of ( 3 X 1.008 amu) = 3.024 amu . The formula mass of ammonia is therefore (14.01 amu + 3.024 amu) = 17.03 amu, and its percent composition is:

% N = (14.01  / 17.03) X 100 = 82.2%

% H = (3.024 / 17.03) X 100 = 18.8 %

This same approach may be taken considering a pair of molecules, a dozen molecules, or a mole of molecules, etc. The latter amount is most convenient and would simply involve the use of molar masses instead of atomic and formula masses. As long as the molecular or empirical formula of the compound in question is known, the percent composition may be derived from the atomic or molar masses of the compound’s elements

Determination of Empirical Formulas :

The most common approach to determining a compound’s chemical formula is to first measure the masses of its constituent elements. However, keep in mind that chemical formulas represent the relative numbers, not masses, of atoms in the substance. Therefore, any experimentally derived data involving mass must be used to derive the corresponding numbers of atoms in the compound. This is accomplished using molar masses to convert the mass of each element to a number of moles. These molar amounts are used to compute whole-number ratios that can be used to derive the empirical formula of the substance

In summary, empirical formulas are derived from experimentally measured element masses by:

  1. Deriving the number of moles of each element from its mass
  2. Dividing each element’s molar amount by the smallest molar amount to yield subscripts for a tentative empirical formula
  3. Multiplying all coefficients by an integer, if necessary, to ensure that the smallest whole-number ratio of subscripts is obtained

Below Figure outlines this procedure in flow chart fashion for a substance containing elements A and X.

Finally, with regard to deriving empirical formulas, consider instances in which a compound’s percent composition is available rather than the absolute masses of the compound’s constituent elements. In such cases, the percent composition can be used to calculate the masses of elements present in any convenient mass of compound; these masses can then be used to derive the empirical formula in the usual fashion.

Derivation of Molecular Formulas

Recall that empirical formulas are symbols representing the relative numbers of a compound’s elements. Determining the absolute numbers of atoms that compose a single molecule of a covalent compound requires knowledge of both its empirical formula and its molecular mass or molar mass. These quantities may be determined experimentally by various measurement techniques. Molecular mass, for example, is often derived from the mass spectrum of the compound  . Molar mass can be measured by a number of experimental methods

Molecular formulas are derived by comparing the compound’s molecular or molar mass to its empirical formula mass. As the name suggests, an empirical formula mass is the sum of the average atomic masses of all the atoms represented in an empirical formula. If the molecular (or molar) mass of the substance is known, it may be divided by the empirical formula mass to yield the number of empirical formula units per molecule (n)

Molarity

Mixtures—samples of matter containing two or more substances physically combined—are more commonly encountered in nature than are pure substances.

Similar to a pure substance, the relative composition of a mixture plays an important role in determining its properties. The relative amount of oxygen in a planet’s atmosphere determines its ability to sustain aerobic life. The relative amounts of iron, carbon, nickel, and other elements in steel (a mixture known as an “alloy”) determine its physical strength and resistance to corrosion. The relative amount of the active ingredient in a medicine determines its effectiveness in achieving the desired pharmacological effect. The relative amount of sugar in a beverage determines its sweetness . This section will describe one of the most common ways in which the relative compositions of mixtures may be quantified.

Sugar is one of many components in the complex mixture known as coffee. The amount of sugar in a given amount of coffee is an important determinant of the beverage’s sweetness. (credit: Jane Whitney)

Solutions

Solutions have previously been defined as homogeneous mixtures, meaning that the composition of the mixture (and therefore its properties) is uniform throughout its entire volume. Solutions occur frequently in nature and have also been implemented in many forms of manmade technology. A more thorough treatment of solution properties is provided in the chapter on solutions and colloids, but provided here is an introduction to some of the basic properties of solutions.

The relative amount of a given solution component is known as its concentration. Often, though not always, a solution contains one component with a concentration that is significantly greater than that of all other components. This component is called the solvent and may be viewed as the medium in which the other components are dispersed, or dissolved. Solutions in which water is the solvent are, of course, very common on our planet. A solution in which water is the solvent is called an aqueous solution.

A solute is a component of a solution that is typically present at a much lower concentration than the solvent. Solute concentrations are often described with qualitative terms such as dilute (of relatively low concentration) and concentrated (of relatively high concentration).

Concentrations may be quantitatively assessed using a wide variety of measurement units, each convenient for particular applications. Molarity (M) is a useful concentration unit for many applications in chemistry.

Molarity is defined as the number of moles of solute in exactly 1 liter (1 L) of the solution:

ie  [ M = ( mol Solute / L solution) ]

Mass Percentage

Percentages are also commonly used to express the composition of mixtures, including solutions. The mass percentage of a solution component is defined as the ratio of the component’s mass to the solution’s mass, expressed as a percentage

Mass Percentage = (Mass of Component / Mass of Solution) X 100 %

Mass percentage is also referred to by similar names such as percent mass, percent weight, weight/weight percent, and other variations on this theme. The most common symbol for mass percentage is simply the percent sign, %, although more detailed symbols are often used including %mass, %weight, and (w/w)%. Use of these more detailed symbols can prevent confusion of mass percentages with other types of percentages, such as volume percentages .

Mass percentages are popular concentration units for consumer products. The label of a typical liquid bleach bottle cites the concentration of its active ingredient, sodium hypochlorite (NaOCl), as being 7.4%. A 100.0-g sample of bleach would therefore contain 7.4 g of NaOCl

Liquid bleach is an aqueous solution of sodium hypochlorite (NaOCl). This brand has a concentration of 7.4% NaOCl by mass

Volume Percentage

Liquid volumes over a wide range of magnitudes are conveniently measured using common and relatively inexpensive laboratory equipment. The concentration of a solution formed by dissolving a liquid solute in a liquid solvent is therefore often expressed as a volume percentage, %vol or (v/v)%

Volume Percentage = (Volume Solute / Volume Solution) X 100 %

Mass-Volume Percentage

“Mixed” percentage units, derived from the mass of solute and the volume of solution, are popular for certain biochemical and medical applications. A mass-volume percent is a ratio of a solute’s mass to the solution’s volume expressed as a percentage. The specific units used for solute mass and solution volume may vary, depending on the solution. For example, physiological saline solution, used to prepare intravenous fluids, has a concentration of 0.9% mass/volume (m/v), indicating that the composition is 0.9 g of solute per 100 mL of solution. The concentration of glucose in blood (commonly referred to as “blood sugar”) is also typically expressed in terms of a mass-volume ratio. Though not expressed explicitly as a percentage, its concentration is usually given in milligrams of glucose per deciliter (100 mL) of blood

“Mixed” mass-volume units are commonly encountered in medical settings. (a) The NaCl concentration of physiological saline is 0.9% (m/v). (b) This device measures glucose levels in a sample of blood. The normal range for glucose concentration in blood (fasting) is around 70–100 mg/dL. (credit a: modification of work by “The National Guard”/Flickr; credit b: modification of work by Biswarup Ganguly)

Parts per Million and Parts per Billion

Very low solute concentrations are often expressed using appropriately small units such as parts per million (ppm) or parts per billion (ppb). Like percentage (“part per hundred”) units, ppm and ppb may be defined in terms of masses, volumes, or mixed mass-volume units. There are also ppm and ppb units defined with respect to numbers of atoms and molecules

Both ppm and ppb are convenient units for reporting the concentrations of pollutants and other trace contaminants in water. Concentrations of these contaminants are typically very low in treated and natural waters, and their levels cannot exceed relatively low concentration thresholds without causing adverse effects on health and wildlife. For example, the EPA has identified the maximum safe level of fluoride ion in tap water to be 4 ppm. Inline water filters are designed to reduce the concentration of fluoride and several other trace- level contaminants in tap water

  • In some areas, trace-level concentrations of contaminants can render unfiltered tap water unsafe for drinking and cooking. (b) Inline water filters reduce the concentration of solutes in tap water. (credit a: modification of work by Jenn Durfey; credit b: modification of work by “vastateparkstaff”/Wikimedia commons)

Stoichiometry of Chemical Reactions

The description of  how to symbolize chemical reactions using chemical equations, how   to classify some common chemical reactions by identifying patterns of reactivity, and how to determine the quantitative relations between the amounts of substances involved in chemical reaction is called  the reaction stoichiometry.

Writing and Balancing Chemical Equations

When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. Extending this symbolism to represent both the identities and the relative quantities of substances undergoing a chemical (or physical) change involves writing and balancing a chemical equation.

Consider as an example the reaction between one methane molecule (CH4) and two diatomic oxygen molecules (O2) to produce one carbon dioxide molecule (CO2) and two water molecules (H2O). The chemical equation representing this process is provided in the upper half of the below figure, with space-filling molecular models shown in the lower half of the figure.

The reaction between methane and oxygen to yield carbon dioxide and water (shown at bottom) may be represented by a chemical equation using formulas (top).

This example illustrates the fundamental aspects of any chemical equation:

  1. The substances undergoing reaction are called reactants, and their formulas are placed on the left side of the equation.
  2. The substances generated by the reaction are called products, and their formulas are placed on the right side of the equation.
  3. Plus signs (+) separate individual reactant and product formulas, and an arrow -> separates the reactant and product (left and right) sides of the equation.
  4. The relative numbers of reactant and product species are represented by coefficients (numbers placed immediately to the left of each formula). A coefficient of 1 is typically omitted.

It is common practice to use the smallest possible whole-number coefficients in a chemical equation, as is done in this example. Realize, however, that these coefficients represent the relative numbers of reactants and products, and, therefore, they may be correctly interpreted as ratios. Methane and oxygen react to yield carbon dioxide and water in a 1:2:1:2 ratio. This ratio is satisfied if the numbers of these molecules are, respectively, 1-2-1-2 , or 2-4-2-4, or 3-6-3-6, and so on . Likewise, these coefficients may be interpreted with regard to any amount (number) unit, and so this equation may be correctly read in many ways, including:

  • One methane molecule and two oxygen molecules react to yield one carbon dioxide molecule and two water molecules.
  • One dozen methane molecules and two dozen oxygen molecules react to yield one dozen carbon dioxide molecules and two dozen water molecules.
  • One mole of methane molecules and 2 moles of oxygen molecules react to yield 1 mole of carbon dioxide molecules and 2 moles of water molecules

Regardless of the absolute numbers of molecules involved, the ratios between numbers of molecules of each species that react (the reactants) and molecules of each species that form (the products) are the same and are given by the chemical reaction equation

Balancing Equations

A chemical equation is balanced, if  equal numbers of atoms for each element involved in the reaction are represented on the reactant and product sides. This is a requirement the equation must satisfy to be consistent with the law of conservation of matter. It may be confirmed by simply summing the numbers of atoms on either side of the arrow and comparing these sums to ensure they are equal. Note that the number of atoms for a given element is calculated by multiplying the coefficient of any formula containing that element by the element’s subscript in the formula. If an element appears in more than one formula on a given side of the equation, the number of atoms represented in each must be computed and then added together

A balanced chemical equation provides a great deal of information in a very succinct format. Chemical formulas provide the identities of the reactants and products involved in the chemical change, allowing classification of the reaction. Coefficients provide the relative numbers of these chemical species, allowing a quantitative assessment of the relationships between the amounts of substances consumed and produced by the reaction. These quantitative relationships are known as the reaction’s stoichiometry, a term derived from the Greek words stoicheion (meaning “element”) and metron (meaning “measure”). In this module, the use of balanced chemical equations for various stoichiometric applications is explored

The general approach to using stoichiometric relationships is similar in concept to the way people go about many common activities. Food preparation, for example, offers an appropriate comparison. A recipe for making eight pancakes calls for 1 cup pancake mix, ¾ cup milk , and one egg. The “equation” representing the  preparation of pancakes per this recipe is

1 cup pancake mix + ¾ cup milk + 1 egg ——> 8 pancakes

If two dozen pancakes are needed for a big family breakfast, the ingredient amounts must be increased proportionally according to the amounts given in the recipe. For example, the number of eggs required to make 24 pancakes is

24 pancakes X ( 1 egg / 8 pancakes) = 3 eggs

Balanced chemical equations are used in much the same fashion to determine the amount of one reactant required to react with a given amount of another reactant, or to yield a given amount of product, and so forth. The coefficients in the balanced equation are used to derive stoichiometric factors that permit computation of the desired quantity

Numerous variations on the beginning and ending computational steps are possible depending upon what particular quantities are provided and sought (volumes, solution concentrations, and so forth). Regardless of the details, all these calculations share a common essential component: the use of stoichiometric factors derived from balanced chemical equations. Below Figure  provides a general outline of the various computational steps associated with many reaction stoichiometry calculations.

Reaction Yields

The relative amounts of reactants and products represented in a balanced chemical equation are often referred to as stoichiometric amounts. All the exercises of the preceding module involved stoichiometric amounts of reactants. For example, when calculating the amount of product generated from a given amount of reactant, it was assumed that any other reactants required were available in stoichiometric amounts (or greater).

Limiting Reactant

Consider another food analogy, making grilled cheese sandwiches

1 slice of cheese + 2 slices of Bread ———->1 sandwich

Stoichiometric amounts of sandwich ingredients for this recipe are bread and cheese slices in a 2:1 ratio

If you are Provided with 28 slices of bread and 11 slices of cheese, you may prepare 11 sandwiches per the provided recipe, using all the provided cheese and having six slices of bread left over. In this scenario, the number of sandwiches prepared has been limited by the number of cheese slices, and the bread slices have been provided in excess.

Consider this concept now with regard to a chemical process, the reaction of hydrogen with chlorine to yield  hydrogen chloride

H2​+Cl2 →2HCl

The balanced equation shows the hydrogen and chlorine react in a 1:1 stoichiometric ratio. If these reactants are provided in any other amounts, one of the reactants will nearly always be entirely consumed, thus limiting the amount of product that may be generated. This substance is the limiting reactant, and the other substance is the excess reactant. Identifying the limiting and excess reactants for a given situation requires computing the molar amounts of each reactant provided and comparing them to the stoichiometric amounts represented in the balanced chemical equation. For example, imagine combining 3 moles of H2 and 2 moles of Cl2. This represents a 3:2 (or 1.5:1) ratio of hydrogen to chlorine present for reaction, which is greater than the stoichiometric ratio of 1:1. Hydrogen, therefore, is present in excess, and chlorine is the limiting reactant.

Reaction of all the provided chlorine (2 mol) will consume 2 mol of the 3 mol of hydrogen provided, leaving 1 mol of hydrogen unreacted.

An alternative approach to identifying the limiting reactant involves comparing the amount of product expected for the complete reaction of each reactant. Each reactant amount is used to separately calculate the amount of product that would be formed per the reaction’s stoichiometry. The reactant yielding the lesser amount of product is the limiting reactant

Mole Fraction and Molality

Several units commonly used to express the concentrations of solution components have been seen ,  each providing certain benefits for use in different applications. For example, molarity (M) is a convenient unit for use in stoichiometric calculations, since it is defined in terms of the molar amounts of solute species

 [ M = ( mol Solute / L solution) ]

Because solution volumes vary with temperature, molar concentrations will likewise vary. When expressed as molarity, the concentration of a solution with identical numbers of solute and solvent species will be different at different temperatures, due to the contraction/expansion of the solution. More appropriate for calculations involving many colligative properties are mole-based concentration units whose values are not dependent on temperature. Two such units are mole fraction  and molality.

The mole fraction, X, of a component is the ratio of its molar amount to the total number of moles of all solution components . By this definition, the sum of mole fractions for all solution components (the solvent and all solutes) is equal to one.

Molality is a concentration unit defined as the ratio of the numbers of moles of solute to the mass of the solvent in kilograms

ie [ m = mol Solute / Kg Solvent]

Since these units are computed using only masses and molar amounts, they do not vary with temperature and, thus, are better suited for applications requiring temperature-independent concentrations, including several colligative properties

Take Quiz

1. Write the symbol for each of the following ions:

a) the ion with a 1+ charge, atomic number 55, and mass number 133
b) the ion with 54 electrons, 53 protons, and 74 neutrons
c) the ion with atomic number 15, mass number 31, and a 3− charge
d) the ion with 24 electrons, 30 neutrons, and a 3+ charge

ANSWER

a) The ion with a 1+ charge, atomic number 55, and mass number 133 is the cesium ion.
b) The ion with 54 electrons, 53 protons, and 74 neutrons is the iodide ion.
c) The ion with atomic number 15, mass number 31, and a 3− charge is the phosphide ion.
d) The ion with 24 electrons, 30 neutrons, and a 3+ charge is the cobalt(III) ion.

2. Determine the number of protons, neutrons, and electrons in the following isotopes that are used in medical diagnoses:
a) atomic number 9, mass number 18, charge of 1−
b) atomic number 43, mass number 99, charge of 7+
c) atomic number 53, atomic mass number 131, charge of 1−
d) atomic number 81, atomic mass number 201, charge of 1+

ANSWER

Let’s determine the number of protons, neutrons, and electrons for each given isotope:
a) **Atomic number 9, mass number 18, charge of 1−**
– Protons: 9 (since the atomic number is 9)
– Neutrons: 18 – 9 = 9 (mass number – atomic number)
– Electrons: 9 + 1 = 10 (since the charge is 1−, there is one extra electron)
**Summary:**
– Protons: 9
– Neutrons: 9
– Electrons: 10

b) **Atomic number 43, mass number 99, charge of 7+**
– Protons: 43 (since the atomic number is 43)
– Neutrons: 99 – 43 = 56 (mass number – atomic number)
– Electrons: 43 – 7 = 36 (since the charge is 7+, there are seven fewer electrons) **Summary:**
– Protons: 43
– Neutrons: 56
– Electrons: 36

c) **Atomic number 53, mass number 131, charge of 1−**
– Protons: 53 (since the atomic number is 53)
– Neutrons: 131 – 53 = 78 (mass number – atomic number)

– Electrons: 53 + 1 = 54 (since the charge is 1−, there is one extra electron) **Summary:**
– Protons: 53
– Neutrons: 78
– Electrons: 54

d) **Atomic number 81, mass number 201, charge of 1+**
– Protons: 81 (since the atomic number is 81)
– Neutrons: 201 – 81 = 120 (mass number – atomic number)
– Electrons: 81 – 1 = 80 (since the charge is 1+, there is one fewer electron) **Summary:**
– Protons: 81
– Neutrons: 120
– Electrons: 80

3. An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99 amu, and 8.82% abundance with 21.99 amu. Calculate the average atomic mass of this element

ANSWER

The formula for the average atomic mass is:
Average Atomic Mass = ∑ (Fractional Abundance X Isotopic Mass)
Given:
– Isotope 1: 90.92% abundance with 19.99 amu
– Isotope 2: 0.26% abundance with 20.99 amu
– Isotope 3: 8.82% abundance with 21.99 amu
First, convert the percentages to decimal form (fractional abundances):
– Isotope 1: 90.92% = 0.9092
– Isotope 2: 0.26% = 0.0026
– Isotope 3: 8.82% = 0.0882

Now, calculate the average atomic mass:
Average Atomic Mass = (0.9092 X 19.99) + (0.0026 X 20.99) + (0.0882 X 21.99)
= (18.172108 + 0.054574 + 1.940718)
= 20.1674 amu

4. Average atomic masses listed by IUPAC are based on a study of experimental results. Bromine has two isotopes, 79Br and 81Br, whose masses (78.9183 and 80.9163 amu, respectively) and abundances (50.69% and 49.31%, respectively) were determined in earlier experiments. Calculate the average atomic mass of bromine based on these experiments.

ANSWER

79Br – Mass = 78.9183 amu and Abundance = 50.69% , which is 0.5069 in fractional form
81Br – mass = 80.9163 amu and Abundance = 49.31% , which is 0.4931 in fractional form
Average atomic mass= (0.5069×78.9183)+(0.4931×80.9163) = 79.8909
Hence , the average atomic mass = 79.90 amu

5. Determine the empirical formulas for the following compounds:

(a) caffeine, C8H10N4O2
(b) sucrose, C12H22O11
(c) hydrogen peroxide, H2O2
(d) glucose, C6H12O6
(e) ascorbic acid (vitamin C), C6H8O6

ANSWER

(a) C4H5N2O;
(b) C12H22O11;
(c) HO;
(d) CH2O;
(e) C3H4O3

6. Name the following compounds:

a) CsCl
b) BaO
c) K2 S
d) BeCl2
e) Hbr
f) AlF3

ANSWER

(a) cesium chloride;
(b) barium oxide;
(c) potassium sulfide;
(d) beryllium chloride;
(e) hydrogen bromide;
(f ) aluminum fluoride

7. Write the formulas of the following compounds:
(a) chlorine dioxide
(b) dinitrogen tetraoxide
(c) potassium phosphide
(d) silver(I) sulfide
(e) Aluminium fluoride trihydrate
(f) Silicon dioxide

ANSWER

(a) ClO2;
(b) N2O4;
(c) K3P;
(d) Ag2S;
(e) AIF3•3H2O;
(f ) SiO2

8. Calculate the molecular or formula mass of each of the following:

(a) P4
(b) H2O
(c) Ca(NO3)2
(d) CH3CO2H (acetic acid)
(e) C12H22O11 (sucrose, cane sugar)

ANSWER

(a) 123.896 amu;
(b) 18.015 amu;
(c) 164.086 amu;
(d) 60.052 amu;
(e) 342.297 amu

9. Calculate the molar mass of each of the following:
a) S8
b) C5H12
c) Sc2(SO4)3
d) CH3COCH3 (acetone)
e) C6H12O6 (glucose)

ANSWER

(a) 256.48 g/mol;
(b) 72.150 g mol−1;
(c) 378.103 g mol−1;
(d) 58.080 g mol−1;
(e) 180.158 g mol−1

10. Determine the mass of each of the following:
(a) 2.345 mol LiCl
(b) 0.0872 mol acetylene, C2H2
(c) 3.3 X 10-2 mol Na2CO3
(d)1.23 X 103 mol Fructose, C6H12O6
(e) 0.5758 mol FeSO4(H2O)7

ANSWER

(a) 99.41 g;
(b) 2.27 g;
(c) 3.5 g;
(d) 222 kg;
(e) 160.1 g

11. Determine which of the following contains the greatest mass of aluminum: 122 g of AlPO4, 266 g of Al2Cl6, or 225 g of Al2S3

ANSWER

AlPO4: 1.000 mol, or 26.98 g Al;
Al2Cl6: 1.994 mol, or 53.74 g Al;
Al2S3: 3.00 mol, or 80.94 g Al;
Hence , The Al2S3 sample thus contains the greatest mass of Al.

12. A compound of carbon and hydrogen contains 92.3% C and has a molar mass of 78.1 g/mol. What is its molecular formula ?

ANSWER

C6H6

13. Calculate the number of moles and the mass of the solute in each of the following solutions:
a) 2.00 L of 18.5 M H2SO4, concentrated sulfuric acid
b) 100.0 mL of 3.8 X 10-6 M NaCN , the minimum lethal concentration of sodium cyanide in blood serum
c) 5.50 L of 13.3 M H2CO, the formaldehyde used to “fix” tissue samples
d) 325 mL of 1.8 X 10-6 M FeSO4, the minimum concentration of iron sulfate detectable by taste in drinking water

ANSWER

a) 37.0 mol H2SO4, , 3.63 X 103 g H2SO4
b) 3.8 X 10-7 mol NaCN , 1.9 X 10-5 g NaCN
c) 73.2 mol H2CO,2.20 kg H2CO
d) 5.9 X 10-7 mol FeSO4, 8.9 X 10-5 g FeSO4

14. Calculate the molarity of each of the following solutions:
a) 0.195 g of cholesterol, C27H46O, in 0.100 L of serum, the average concentration of cholesterol in human serum
b) 4.25 g of NH3 in 0.500 L of solution, the concentration of NH3 in household ammonia
c) 1.49 kg of isopropyl alcohol, C3H7OH, in 2.50 L of solution, the concentration of isopropyl alcohol in rubbing alcohol
d) 0.029 g of I2 in 0.100 L of solution, the solubility of I2 in water at 20 °C

ANSWER

(a) 5.04 X 10-2 M;
(b) 0.499 M;
(c) 9.92 M;
(d) 1.1 X 10 -3 M

15. What mass of solid NaOH (97.0% NaOH by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 10.0% solution is 1.109 g/mL.

ANSWER

114 g

16. Write a balanced molecular equation describing each of the following chemical reactions.
(a) Solid calcium carbonate is heated and decomposes to solid calcium oxide and carbon dioxide gas.
(b) Gaseous butane, C4H10, reacts with diatomic oxygen gas to yield gaseous carbon dioxide and water vapor.
(c) Aqueous solutions of magnesium chloride and sodium hydroxide react to produce solid magnesium hydroxide and aqueous sodium chloride.
(d) Water vapor reacts with sodium metal to produce solid sodium hydroxide and hydrogen gas.

ANSWER

a) CaCO3(s)−>CaO(s)+CO2(g)
b) 2 C 4 H 10 (g)+13O2 (g)−>8CO 2 (g)+10H 2 O(g)
c) MgCl2 (aq)+2NaOH(aq)−>Mg(OH)2 (s)+2NaCl(aq)
d) 2H 2 O(g)+2Na(s)−>2NaOH(s)+H 2(g)

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Basic Concepts of Chemistry – I

Chemistry: The Central Science

Chemistry is sometimes referred to as “the central science” due to its interconnectedness with a vast array of other STEM disciplines (STEM stands for areas of study in the science, technology, engineering, and math fields). Chemistry and the language of chemists play vital roles in biology, medicine, materials science, forensics, environmental science, and many other fields . The basic principles of physics are essential for understanding many aspects of chemistry, and there is extensive overlap between many subdisciplines within the two fields, such as chemical physics and nuclear chemistry. Mathematics, computer science, and information theory provide important tools that help us calculate, interpret, describe, and generally make sense of the chemical world. Biology and chemistry converge in biochemistry, which is crucial in  understanding the many complex factors and processes that keep living organisms (such as us) alive. Chemical engineering, materials science, and nanotechnology combine chemical principles and empirical findings to produce useful substances, ranging from gasoline to fabrics to electronics. Agriculture, food science, veterinary science, and brewing and wine making help provide sustenance in the form of food and drink to the world’s population. Medicine, pharmacology, biotechnology, and botany identify and produce substances that help keep us healthy. Environmental science, geology, oceanography, and atmospheric science incorporate many chemical ideas to help us better understand and protect our physical world. Chemical ideas are used to help understand the universe in astronomy and cosmology.

The Scientific Method

Chemistry is a science based on observation and experimentation. Doing chemistry involves attempting to answer questions and explain observations in terms of the laws and theories of chemistry, using procedures that are accepted by the scientific community. There is no single route to answering a question or explaining an observation, but there is an aspect common to every approach: Each uses knowledge based on experiments that can be reproduced to verify the results. Some routes involve a hypothesis, a tentative explanation of

observations that acts as a guide for gathering and checking information. A hypothesis is tested by experimentation, calculation, and/or comparison with the experiments of others and then refined as needed.

Some hypotheses are attempts to explain the behavior that is summarized in laws. The laws of science summarize a vast number of experimental observations, and describe or predict some facet of the natural world. If such a hypothesis turns out to be capable of explaining a large body of experimental data, it can reach the status of a theory. Scientific theories are well-substantiated, comprehensive, testable explanations of particular aspects of nature. Theories are accepted because they provide satisfactory explanations, but they can be modified if new data become available. The path of discovery that leads from question and observation to law or hypothesis to theory, combined with experimental verification of the hypothesis and any necessary modification of the theory, is called the scientific method

Phases and Classification of Matter

Matter is defined as anything that occupies space and has mass, and it is all around us. Solids and liquids are more obviously matter: We can see that they take up space, and their weight tells us that they have mass. Gases are also matter; if gases did not take up space, a balloon would not inflate (increase its volume) when filled with gas. Solids, liquids, and gases are the three states of matter commonly found on earth .

A solid is rigid and possesses a definite shape. A liquid flows and takes the shape of its container, except that it forms a flat or slightly curved upper surface when acted upon by gravity. (In zero gravity, liquids assume a spherical shape.) Both liquid and solid samples have volumes that are very nearly independent of pressure. A gas takes both the shape and volume of its container.

A fourth state of matter, plasma, occurs naturally in the interiors of stars. A plasma is a gaseous state of matter that contains appreciable numbers of electrically charged particles . The presence of these charged particles imparts unique properties to plasmas that justify their classification as a state of matter distinct from gases. In addition to stars, plasmas are found in some other high-temperature environments (both natural and man-made), such as lightning strikes, certain television screens, and specialized analytical instruments used to detect trace amounts of metals

Some samples of matter appear to have properties of solids, liquids, and/or gases at the same time. This can occur when the sample is composed of many small pieces. For example, we can pour sand as if it were a liquid because it is composed of many small grains of solid sand. Matter can also have properties of more than one state when it is a mixture, such as with clouds. Clouds appear to behave somewhat like gases, but they are actually mixtures of air (gas) and tiny particles of water (liquid or solid).

The mass of an object is a measure of the amount of matter in it. One way to measure an object’s mass is to measure the force it takes to accelerate the object. It takes much more force to accelerate a car than a bicycle because the car has much more mass. A more common way to determine the mass of an object is to use a balance to compare its mass with a standard mass.

Although weight is related to mass, it is not the same thing. Weight refers to the force that gravity exerts on an object. This force is directly proportional to the mass of the object. The weight of an object changes as the force of gravity changes, but its mass does not. An astronaut’s mass does not change just because she goes to the moon. But her weight on the moon is only one-sixth her earth-bound weight because the moon’s gravity is only one-sixth that of the earth’s. She may feel “weightless” during her trip when she experiences negligible external forces (gravitational or any other), although she is, of course, never “massless.”

The law of conservation of matter summarizes many scientific observations about matter: It states that there is no detectable change in the total quantity of matter present when matter converts from one type to another (a chemical change) or changes among solid, liquid, or gaseous states (a physical change).

Classifying Matter

Matter can be classified into several categories. Two broad categories are mixtures and pure substances. A pure substance has a constant composition. All specimens of a pure substance have exactly the same makeup and properties. Any sample of sucrose (table sugar) consists of 42.1% carbon, 6.5% hydrogen, and 51.4% oxygen by mass. Any sample of sucrose also has the same physical properties, such as melting point, color, and sweetness, regardless of the source from which it is isolated.

Pure substances may be divided into two classes: elements and compounds. Pure substances that cannot be broken down into simpler substances by chemical changes are called elements. Iron, silver, gold, aluminum, sulfur, oxygen, and copper are familiar examples of the more than 100 known elements, of which about 90 occur naturally on the earth, and two dozen or so have been created in laboratories.

Pure substances that are comprised of two or more elements are called compounds. Compounds may be broken down by chemical changes to yield either elements or other compounds, or both. Mercury(II) oxide, an orange, crystalline solid, can be broken down by heat into the elements mercury and oxygen .

When heated in the absence of air, the compound sucrose is broken down into the element carbon and the compound water. (The initial stage of this process, when the sugar is turning brown, is known as caramelization—this is what imparts the characteristic sweet and nutty flavor to caramel apples, caramelized onions, and caramel). Silver(I) chloride is a white solid that can be broken down into its elements, silver and chlorine, by absorption of light. This property is the basis for the use of this compound in photographic films and photochromic eyeglasses (those with lenses that darken when exposed to light

The properties of combined elements are different from those in the free, or uncombined, state. For example, white crystalline sugar (sucrose) is a compound resulting from the chemical combination of the element carbon, which is a black solid in one of its uncombined forms, and the two elements hydrogen and oxygen, which are colorless gases when uncombined. Free sodium, an element that is a soft, shiny, metallic solid, and free chlorine, an element that is a yellow-green gas, combine to form sodium chloride (table salt), a compound that is a white, crystalline solid.

A mixture is composed of two or more types of matter that can be present in varying amounts and can be separated by physical changes, such as evaporation (you will learn more about this later). A mixture with a composition that varies from point to point is called a heterogeneous mixture. Some examples of heterogeneous mixtures are chocolate chip cookies (we can see the separate bits of chocolate, nuts, and cookie dough) and granite (we can see the quartz, mica, feldspar, and more).

Although there are just over 100 elements, tens of millions of chemical compounds result from different combinations of these elements. Each compound has a specific composition and possesses definite chemical and physical properties that distinguish it from all other compounds. And, of course, there are innumerable ways to combine elements and compounds to form different mixtures. A summary of how to distinguish between the various major classifications of matter is shown in the below figure

Eleven elements make up about 99% of the earth’s crust and atmosphere . Oxygen constitutes nearly one-half and silicon about one-quarter of the total quantity of these elements. A majority of elements on earth are found in chemical combinations with other elements; about one-quarter of the elements are also found in the free state

Elemental Composition of Earth

Element Symbol Percent Mass Element   Symbol   Percent Mass
  oxygen O 49.20 chlorine Cl 0.19
silicon Si 25.67 phosphorus P 0.11
aluminum Al 7.50 manganese Mn 0.09
iron Fe 4.71 carbon C 0.08
calcium Ca 3.39 sulfur S 0.06
sodium Na 2.63 barium Ba 0.04
potassium K 2.40 nitrogen N 0.03
magnesium Mg 1.93 fluorine F 0.03
hydrogen H 0.87 strontium Sr 0.02
titanium Ti 0.58 all others 0.47

Atoms and Molecules

An atom is the smallest particle of an element that has the properties of that element and can enter into a chemical combination. Consider the element gold, for example. Imagine cutting a gold nugget in half, then cutting one of the halves in half, and repeating this process until a piece of gold remained that was so small that it could not be cut in half (regardless of how tiny your knife may be). This minimally sized piece of gold is an atom (from the Greek atomos, meaning “indivisible”). This atom would no longer be gold if it were divided any further

An atom is so small that its size is difficult to imagine. One of the smallest things we can see with our unaided eye is a single thread of a spider web: These strands are about 1/10,000 of a centimeter (0.0001 cm) in diameter. Although the cross-section of one strand is almost impossible to see without a microscope, it is huge on an atomic scale

The above images provide an increasingly closer view: (a) a cotton boll, (b) a single cotton fiber viewed under an optical microscope (magnified 40 times), (c) an image of a cotton fiber obtained with an electron microscope (much higher magnification than with the optical microscope); and (d and e) atomic-level models of the fiber (spheres of different colors represent atoms of different elements). (credit c: modification of work by “Featheredtar”/Wikimedia Commons)

An atom is so light that its mass is also difficult to imagine. A billion lead atoms (1,000,000,000 atoms) weigh about 3 X 10−13 grams, a mass that is far too light to be weighed on even the world’s most sensitive balances. It would require over 300,000,000,000,000 lead atoms (300 trillion, or 3      1014) to be weighed, and they would weigh only 0.0000001 gram

It is rare to find collections of individual atoms. Only a few elements, such as the gases helium, neon, and argon, consist of a collection of individual atoms that move about independently of one another. Other elements, such as the gases hydrogen, nitrogen, oxygen, and chlorine, are composed of units that consist of pairs of atoms . One form of the element phosphorus consists of units composed of four phosphorus atoms. The element sulfur exists in various forms, one of which consists of units composed of eight sulfur atoms. These units are called molecules. A molecule consists of two or more atoms joined by strong forces called chemical bonds. The atoms in a molecule move around as a unit, much like the cans of soda in a six-pack or a bunch of keys joined together on a single key ring. A molecule may consist of two or more identical atoms, as in the molecules found in the elements hydrogen, oxygen, and sulfur, or it may consist of two or more different atoms, as in the molecules found in water. Each water molecule is a unit that contains two hydrogen atoms and one oxygen atom. Each glucose molecule is a unit that contains 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. Like atoms, molecules are incredibly small and light.

Physical and Chemical Properties

The characteristics that distinguish one substance from another are called properties. A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Some physical properties, such as density and color, may be observed without changing the physical state of the matter. Other physical properties, such as the melting temperature of iron or the freezing temperature of water, can only be observed as matter undergoes a physical change. A physical change is a change in the state or properties of matter without any accompanying change in the chemical identities of the substances contained in the matter. Physical changes are observed when wax melts, when sugar dissolves in coffee, and when steam condenses into liquid water . Other examples of physical changes include magnetizing and demagnetizing metals (as is done with common antitheft security tags) and grinding solids into powders (which can sometimes yield noticeable changes in color). In each of these examples, there is a change in the physical state, form, or properties of the substance, but no change in its chemical composition

(a) Wax undergoes a physical change when solid wax is heated and forms liquid wax. (b) Steam condensing inside a cooking pot is a physical change, as water vapor is changed into liquid water. (credit a: modification of work by “95jb14”/Wikimedia Commons; credit b: modification of work by “mjneuby”/Flickr)

The change of one type of matter into another type (or the inability to change) is a chemical property. Examples of chemical properties include flammability, toxicity, acidity, and many other types of reactivity. Iron, for example, combines with oxygen in the presence of water to form rust; chromium does not oxidize . Nitroglycerin is very dangerous because it explodes easily; neon poses almost no hazard because it is very unreactive

(a) One of the chemical properties of iron is that it rusts; (b) one of the chemical properties of chromium is that it does not. (credit a: modification of work by Tony Hisgett; credit b: modification of work by “Atoma”/Wikimedia Commons)

A chemical change always produces one or more types of matter that differ from the matter present before the change. The formation of rust is a chemical change because rust is a different kind of matter than the iron, oxygen, and water present before the rust formed. The explosion of nitroglycerin is a chemical change because the gases produced are very different kinds of matter from the original substance. Other examples of chemical changes include reactions that are performed in a lab (such as copper reacting with nitric acid), all forms of combustion (burning), and food being cooked, digested, or rotting

While many elements differ dramatically in their chemical and physical properties, some elements have similar properties. For example, many elements conduct heat and electricity well, whereas others are poor conductors. These properties can be used to sort the elements into three classes: metals (elements that conduct well), nonmetals (elements that conduct poorly), and metalloids (elements that have intermediate conductivities).

The periodic table is a table of elements that places elements with similar properties close together . You will learn more about the periodic table as you continue your study of chemistry

The periodic table shows how elements may be grouped according to certain similar properties. Note the background color denotes whether an element is a metal, metalloid, or nonmetal, whereas the element symbol color indicates whether it is a solid, liquid, or gas.

Measurements

Measurements provide much of the information that informs the hypotheses, theories, and laws describing the behavior of matter and energy in both the macroscopic and microscopic domains of chemistry. Every measurement provides three kinds of information:

  1. the size or magnitude of the measurement (a number);
  2. a standard of comparison for the measurement (a unit); and
  3.  an indication of the uncertainty of the measurement.

While the number and unit are explicitly represented when a quantity is written, the uncertainty is an aspect of the measurement result that is more implicitly represented and will be discussed later.

The number in the measurement can be represented in different ways, including decimal form and scientific notation. (Scientific notation is also known as exponential notation). For example, the maximum takeoff weight of a Boeing 777-200ER airliner is 298,000 kilograms, which can also be written as 2.98 X 105 kg. The mass of the average mosquito is about 0.0000025 kilograms ,  which can be written as  2.5 X 10-6  Kg  .

Units, such as liters, pounds, and centimeters, are standards of comparison for measurements. A 2-liter   

 bottle of a soft drink contains a volume of beverage that is twice that of the accepted volume of 1 liter.  Without units, a number can be meaningless, confusing, or possibly life threatening. Suppose a doctor prescribes phenobarbital to control a patient’s seizures and states a dosage of “100” without specifying units. Not only will this be confusing to the medical professional giving the dose, but the consequences can be dire.

The measurement units for seven fundamental properties (“base units”) are listed in the below table . The standards for these units are fixed by international agreement, and they are called the International System of Units or SI Units (from the French, Le Système International d’Unités). SI units have been used by the United States National Institute of Standards and Technology (NIST) since 1964. Units for other properties may be derived from these seven base units.

Base Units of the SI System

length meter m
mass kilogram kg
time second s
temperature kelvin K
electric current ampere A
amount of substance mole mol
luminous intensity candela cd

Everyday measurement units are often defined as fractions or multiples of other units . Fractional or multiple  SI units are named using a prefix and the name of the base unit. For example, a length of 1000 meters is also called a kilometer because the prefix kilo means “one thousand,” which in scientific notation is 103 (1 kilometer = 1000 m = 103 m). The prefixes used and the powers to which 10 are raised are listed in  the below table

Common Unit Prefixes                                               

femto f 10−15 1 femtosecond (fs) = 1       10−15 s (0.000000000000001 s)
pico p 10−12 1 picometer (pm) = 1       10−12 m (0.000000000001 m)

nano n 10−9 4 nanograms (ng) = 4    10−9 g (0.000000004 g)
micro µ 10−6 1 microliter (μL) = 1        10−6 L (0.000001 L)
milli m 10−3 2 millimoles (mmol) = 2      10−3 mol (0.002 mol)
centi c 10−2 7 centimeters (cm) = 7     10−2 m (0.07 m)
deci d 10−1 1 deciliter (dL) = 1     10−1 L (0.1 L )
kilo k 103 1 kilometer (km) = 1       103 m (1000 m)
mega M 106 3 megahertz (MHz) = 3     106 Hz (3,000,000 Hz)
giga G 109 8 gigayears (Gyr) = 8     109 yr (8,000,000,000 yr)
tera T 1012 5 terawatts (TW) = 5      1012 W (5,000,000,000,000 W)

SI Base Units

The initial units of the metric system, which eventually evolved into the SI system, were established in France during the French Revolution. The original standards for the meter and the kilogram were adopted there in 1799 and eventually by other countries. This section introduces four of the SI base units commonly used in chemistry. Other SI units will be introduced in subsequent chapters.

Length

The standard unit of length in both the SI and original metric systems is the meter (m). A meter was originally specified as 1/10,000,000 of the distance from the North Pole to the equator. It is now defined as the distance light in a vacuum travels in 1/299,792,458 of a second. A meter is about 3 inches longer than a yard  , one meter is about 39.37 inches or 1.094 yards. Longer distances are often reported in kilometers (1 km

= 1000 m = 103 m), whereas shorter distances can be reported in centimeters (1 cm = 0.01 m = 10−2 m) or

millimeters (1 mm = 0.001 m = 10−3 m).

Above figure gives The relative lengths of 1 m, 1 yd, 1 cm, and 1 in. are shown (not actual size), as well as comparisons of 2.54 cm and  1 in., and of 1 m and 1.094 yd

Mass

The standard unit of mass in the SI system is the kilogram (kg). The kilogram was previously defined by the International Union of Pure and Applied Chemistry (IUPAC) as the mass of a specific reference object. This object was originally one liter of pure water, and more recently it was a metal cylinder made from a platinum- iridium alloy with a height and diameter of 39 mm as shown in below figure . In May 2019, this definition was changed to one that is based instead on precisely measured values of several fundamental physical constants. One kilogram is about 2.2 pounds. The gram (g) is exactly equal to 1/1000 of the mass of the kilogram (10−3 kg)

Temperature

Temperature is an intensive property. The SI unit of temperature is the kelvin (K). The IUPAC convention is to use kelvin (all lowercase) for the word, K (uppercase) for the unit symbol, and neither the word “degree” nor the degree symbol (°). The degree Celsius (°C) is also allowed in the SI system, with both the word “degree” and the degree symbol used for Celsius measurements. Celsius degrees are the same magnitude as those of kelvin, but the two scales place their zeros in different places. Water freezes at 273.15 K (0 °C) and boils at 373.15 K (100 °C) by definition, and normal human body temperature is approximately 310 K (37 °C).

Time

The SI base unit of time is the second (s). Small and large time intervals can be expressed with the appropriate prefixes; for example, 3 microseconds = 0.000003 s = 3×10−6 and 5 megaseconds = 5,000,000 s = 5  106 s. Alternatively, hours, days, and years can be used.

Derived SI Units

We can derive many units from the seven SI base units. For example, we can use the base unit of length to define a unit of volume, and the base units of mass and length to define a unit of density.

Volume

Volume is the measure of the amount of space occupied by an object. The standard SI unit of volume is defined by the base unit of length . The standard volume is a cubic meter (m3), a cube with an edge length of exactly one meter. To dispense a cubic meter of water, we could build a cubic box with edge lengths of exactly one meter. This box would hold a cubic meter of water or any other substance.

A more commonly used unit of volume is derived from the decimeter (0.1 m, or 10 cm). A cube with edge lengths of exactly one decimeter contains a volume of one cubic decimeter (dm3). A liter (L) is the more common name for the cubic decimeter. One liter is about 1.06 quarts.

A cubic centimeter (cm3) is the volume of a cube with an edge length of exactly one centimeter. The abbreviation cc (for cubic centimeter) is often used by health professionals. A cubic centimeter is equivalent to a milliliter (mL) and is 1/1000 of a liter.

The relative volumes are shown for cubes of 1 m3, 1 dm3 (1 L), and 1 cm3 (1 mL) (not to scale). (b) The diameter of a dime is compared relative to the edge length of a 1-cm3 (1-mL) cube.

Density

We use the mass and volume of a substance to determine its density. Thus, the units of density are defined by the base units of mass and length. The density of a substance is the ratio of the mass of a sample of the substance to its volume. The SI unit for density is the kilogram per cubic meter (kg/m3). For many situations, however, this is an inconvenient unit, and we often use grams per cubic centimeter (g/cm3) for the densities of solids and liquids, and grams per liter (g/L) for gases. Although there are exceptions, most liquids and solids have densities that range from about 0.7 g/cm3 (the density of petrol ) to 19 g/cm3 (the density of gold). The density of air is about 1.2 g/L

Densities of Common Substances

Solids Liquids   Gases (at 25 °C and 1 atm)
ice (at 0 °C) 0.92 g/cm3 water 1.0 g/cm3 dry air 1.20 g/L
oak (wood) 0.60–0.90 g/cm3 ethanol 0.79 g/cm3 oxygen 1.31 g/L
iron 7.9 g/cm3 acetone 0.79 g/cm3 nitrogen 1.14 g/L
copper 9.0 g/cm3 glycerin 1.26 g/cm3 carbon dioxide 1.80 g/L
lead 11.3 g/cm3 olive oil 0.92 g/cm3 helium 0.16 g/L
silver 10.5 g/cm3 gasoline 0.70–0.77 g/cm3 neon 0.83 g/L
gold 19.3 g/cm3 mercury 13.6 g/cm3 radon 9.1 g/L

While there are many ways to determine the density of an object, perhaps the most straightforward method involves separately finding the mass and volume of the object, and then dividing the mass of the sample by its volume. In the following example, the mass is found directly by weighing, but the volume is found indirectly through length measurements

Density = Mass / Volume

Measurement Uncertainty, Accuracy, and Precision

Counting is the only type of measurement that is free from uncertainty, provided the number of objects being counted does not change while the counting process is underway. The result of such a counting measurement is an example of an exact number. By counting the eggs in a carton, one can determine exactly how many eggs the carton contains. The numbers of defined quantities are also exact. By definition, 1 foot is exactly 12 inches, 1 inch is exactly 2.54 centimeters, and 1 gram is exactly 0.001 kilogram. Quantities derived from measurements other than counting, however, are uncertain to varying extents due to practical limitations of the measurement process used.

Significant Figures in Measurement

The numbers of measured quantities, unlike defined or directly counted quantities, are not exact. To measure the volume of liquid in a graduated cylinder (below figure) ,  you should make a reading at the bottom of the meniscus, the lowest point on the curved surface of the liquid

Refer to the above  illustration . The bottom of the meniscus in this case clearly lies between the 21 and 22 markings, meaning the liquid volume is certainly greater than 21 mL but less than 22 mL. The meniscus appears to be a bit closer to the 22-mL mark than to the 21-mL mark, and so a reasonable estimate of the liquid’s volume would be 21.6 mL. In the number 21.6, then, the digits 2 and 1 are certain, but the 6 is an estimate. Some people might estimate the meniscus position to be equally distant from each of the markings and estimate the tenth-place digit as 5, while others may think it to be even closer to the 22-mL mark and estimate this digit to be 7. Note that it would be pointless to attempt to estimate a digit for the hundredths place, given that the tenths-place digit is uncertain. In general, numerical scales such as the one on this graduated cylinder will permit measurements to one-tenth of the smallest scale division. The scale in this case has 1-mL divisions, and so volumes may be measured to the nearest 0.1 mL.

This concept holds true for all measurements, even if you do not actively make an estimate. If you place a quarter on a standard electronic balance, you may obtain a reading of 6.72 g. The digits 6 and 7 are certain, and the 2 indicates that the mass of the quarter is likely between 6.71 and 6.73 grams. The quarter weighs about 6.72 grams, with a nominal uncertainty in the measurement of ± 0.01 gram. If the coin is weighed on a more sensitive balance, the mass might be 6.723 g. This means its mass lies between 6.722 and 6.724 grams, an uncertainty of 0.001 gram. Every measurement has some uncertainty, which depends on the device used (and the user’s ability). All of the digits in a measurement, including the uncertain last digit, are called significant figures or significant digits. Note that zero may be a measured value; for example, if you stand on a scale that shows weight to the nearest Kg ,  and it shows “120,” then the 1 (hundreds), 2 (tens) and 0 (ones) are all significant (measured) values.

Significant Figures in Calculations

A second important principle of uncertainty is that results calculated from a measurement are at least as uncertain as the measurement itself. Take the uncertainty in measurements into account to avoid misrepresenting the uncertainty in calculated results. One way to do this is to report the result of a calculation with the correct number of significant figures, which is determined by the following three rules for rounding numbers:

  1. When adding or subtracting numbers, round the result to the same number of decimal places as the         number with the least number of decimal places (the least certain value in terms of addition and subtraction).
  2. When multiplying or dividing numbers, round the result to the same number of digits as the number with the least number of significant figures (the least certain value in terms of multiplication and division).
  3. If the digit to be dropped (the one immediately to the right of the digit to be retained) is less than 5, “round down” and leave the retained digit unchanged; if it is more than 5, “round up” and increase the retained digit by 1. If the dropped digit is 5, and it’s either the last digit in the number or it’s followed only by zeros, round up or down, whichever yields an even value for the retained digit. If any nonzero digits follow the dropped 5, round up. (The last part of this rule may strike you as a bit odd, but it’s based on reliable statistics and is aimed at avoiding any bias when dropping the digit “5,” since it is equally close to both possible values of the retained digit.)

Conversion Factors and Dimensional Analysis

A ratio of two equivalent quantities expressed with different measurement units can be used as a unit conversion factor. For example, the lengths of 2.54 cm and 1 inch. are equivalent (by definition), and so a unit conversion factor may be derived from the ratio

Common Conversion Factors

Length    Volume       Mass
1 m = 1.0936 yd 1 L = 1.0567 qt 1 kg = 2.2046 lb
1 in. = 2.54 cm (exact) 1 qt = 0.94635 L 1 lb = 453.59 g
1 km = 0.62137 mi 1 ft3 = 28.317 L 1 (avoirdupois) oz = 28.349 g
1 mi = 1609.3 m 1 tbsp = 14.787 mL 1 (troy) oz = 31.103 g

When a quantity (such as distance in inches) is multiplied by an appropriate unit conversion factor, the quantity is converted to an equivalent value with different units (such as distance in centimeters).

Take Quiz

1. Classify each of the following as an element, a compound, or a mixture:

  • sucrose
  • copper
  • water
  • nitrogen
  • sulfur
  • air

ANSWER

Copper – Element
Water – Compound
Nitrogen – Element
Sulfur – Element
Air – Mixture
Sucrose – Compound

2. Classify each of the following changes as physical or chemical:
a) condensation of steam
b) burning of gasoline
c) souring of milk
d) dissolving of sugar in water
e) melting of gold

ANSWER

a) Condensation of steam – Physical change
b) Burning of gasoline – Chemical change
c) Souring of milk – Chemical change
d) Dissolving of sugar in water – Physical change
e) Melting of gold – Physical change

3. Indicate the SI base units or derived units that are appropriate for the following measurements:

  • the volume of a flu shot or a measles vaccination
  • the mass of the moon
  • the distance from Mumbai to Kolkata City
  • the speed of sound
  • the density of air

ANSWER

The mass of the moon: Kilogram (kg)
The distance from Mumbai to Kolkata City: Meter (m)
The speed of sound: Meters per second (m/s)
The density of air: Kilograms per cubic meter (kg/m³)
The volume of a flu shot or a measles vaccination: Cubic meter (m³) or more commonly, milliliter (mL) for practical use in this context

4. Give the name and symbol of the prefixes used with SI units to indicate multiplication by the following exact quantities.

(a) 103
(b) 10-2
c) 0.1
d) 10-3
(e) 1,000,000
(f ) 0.000001

ANSWER

(a) 103
– Name: Kilo
– Symbol: k
(b) 10-2
– Name: Centi
– Symbol: c
(c) 0.1
– Name: Deci
– Symbol: d
(d) 10-3
– Name: Milli
– Symbol: m
(e) 1,000,000
– Name: Mega
– Symbol: M
(f) 0.000001
– Name: Micro
– Symbol: µ

5. Give the name of the prefix and the quantity indicated by the following symbols that are used with SI base units.
1. m
2. c
3. d
4. G
5. k

ANSWER

c
– Name: Centi
– Quantity: 10−210^{-2}10−2 or 0.01
d
– Name: Deci
– Quantity: 10−110^{-1}10−1 or 0.1
G
– Name: Giga
– Quantity: 10910^9109 or 1,000,000,000

k
– Name: Kilo
– Quantity: 10310^3103 or 1,000

m
– Name: Milli
– Quantity: 10−310^{-3}10−3 or 0.001

6. When elemental iron corrodes it combines with oxygen in the air to ultimately form red brown iron(III) oxide called rust. (a) If a shiny iron nail with an initial mass of 23.2 g is weighed after being coated in a layer of rust, would you expect the mass to have increased, decreased, or remained the same?

ANSWER

When elemental iron corrodes and combines with oxygen from the air to form iron(III) oxide (rust), the mass of the iron nail would increase. This is because the process of rusting involves the addition of oxygen atoms to the iron atoms, resulting in an increase in the overall mass of the nail

7. Yeast converts glucose to ethanol and carbon dioxide during anaerobic fermentation as depicted in the simple chemical equation here
Glucose ———— Ethanol + Carbondioxide
If 200.0 g of glucose is fully converted, what will be the total mass of ethanol and carbon dioxide produced ?

ANSWER

The law of conservation of mass states that the mass of the reactants in a chemical reaction is equal to the mass of the products. Therefore, if 200.0 g of glucose is fully converted during anaerobic fermentation, the total mass of ethanol and carbon dioxide produced will also be 200.0 g

8. The volume of a sample of oxygen gas changed from 10 mL to 11 mL as the temperature changed. Is this a chemical or physical change?

ANSWER

The change in the volume of a sample of oxygen gas from 10 mL to 11 mL as the temperature changes is a physical change. This is because the change involves a physical property (volume) and is reversible, without altering the chemical composition or identity of the oxygen gas.

9. A 2.0-liter volume of hydrogen gas combined with 1.0 liter of oxygen gas to produce 2.0 liters of water vapor. Does oxygen undergo a chemical or physical change?

ANSWER

In the reaction where 2.0 liters of hydrogen gas combine with 1.0 liter of oxygen gas to produce 2.0 liters of water vapor, oxygen undergoes a chemical change. This is because the oxygen molecules react with hydrogen molecules to form a new substance, water (H₂O), which has different chemical properties and composition from the reactant gases.

10. Indicate the SI base units or derived units that are appropriate for the following measurements:
1. the length of a marathon race (26 miles 385 yards)
2. the mass of an automobile
3. the volume of a swimming pool
4. the speed of an airplane
5. the density of gold
6. the area of a football field

ANSWER

Here are the appropriate SI base units or derived units for each measurement:
1. The length of a marathon race (26 miles 385 yards)
– Meter (m)
2. The mass of an automobile
– Kilogram (kg)
3. The volume of a swimming pool
– Cubic meter (m³)
4. The speed of an airplane
– Meters per second (m/s)
5. The density of gold
– Kilograms per cubic meter (kg/m³)
6. The area of a football field
– Square meter (m²)

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Laws of Chemical Combinations

Introduction

Chemistry is the study of matter and its transformations. Understanding the fundamental laws that govern chemical combinations is crucial for comprehending the behaviour of substances and their reactions. In this lesson, we will explore the fundamental laws of chemical combinations, including the Law of Conservation of Mass, the Law of Definite Proportions, and the Law of Multiple Proportions.

Law of Conservation of Mass

The Law of Conservation of Mass states that in any chemical reaction, the total mass of the reactants is equal to the total mass of the products.

This law emphasizes that atoms are neither created nor destroyed during a chemical reaction.

It is represented by the equation: Mass of Reactants = Mass of Products

Here are a few examples that illustrate this principle:

Combustion: When a piece of wood is burned, it undergoes a chemical reaction with oxygen to produce carbon dioxide and water vapor. Despite the physical and chemical changes that occur during the combustion process, the total mass of the system (including the wood, oxygen, carbon dioxide, and water vapor) remains constant.

Precipitation: When a solution of silver nitrate is mixed with a solution of sodium chloride, a precipitation reaction occurs, leading to the formation of a white solid known as silver chloride. Even though new substances are formed in this chemical reaction, the total mass of the system before and after the reaction remains the same.

Photosynthesis: During photosynthesis, plants convert carbon dioxide and water into glucose (a sugar) and oxygen, using energy from sunlight. Despite the complex biochemical reactions that take place within the plant, the total mass of the system (including the reactants and products) remains constant.

Nuclear reactions: In nuclear reactions, such as radioactive decay or nuclear fission, the nuclei of atoms undergo changes, releasing energy and sometimes transforming into different elements. However, the total mass of the reactants and products involved in the nuclear reaction remains constant.

These examples demonstrate that the law of conservation of mass holds true in various physical and chemical processes, affirming that mass is neither created nor destroyed but simply changes form.

Law of Definite Proportions

The Law of Definite Proportions , also known as the Law of Constant Composition was discovered by Joseph Proust . It states that a pure compound always contains the same elements in definite proportions by mass.

Regardless of the source or method of preparation, the ratio of the masses of elements in a compound remains constant.

This law is exemplified by the formula of water, H2O, which always consists of two hydrogen atoms and one oxygen atom in a fixed ratio by mass.

Here are a few examples that illustrate this law with chemical equations:

Water (H2O):

2H2 + O2 → 2H2O

This equation shows that when hydrogen gas (H2) reacts with oxygen gas (O2) in a 2:1 ratio by volume, it forms water (H2O). Regardless of the source of hydrogen and oxygen, the mass ratio of hydrogen to oxygen in water will always be 1:8.

Carbon Dioxide (CO2):

C + O2 → CO2

When carbon (C) combines with oxygen (O2) in a 1:2 ratio by mass, carbon dioxide (CO2) is formed. The law of definite proportions ensures that regardless of the source of carbon and oxygen, the mass ratio of carbon to oxygen in carbon dioxide will always be 1:2.

Ammonia (NH3):

N2 + 3H2 → 2NH3

When nitrogen gas (N2) reacts with hydrogen gas (H2) in a 1:3 ratio by volume, it produces ammonia (NH3). According to the law of definite proportions, regardless of the source of nitrogen and hydrogen, the mass ratio of nitrogen to hydrogen in ammonia will always be 1:3.

Sodium Chloride (NaCl):

Na + Cl2 → 2NaCl

In this equation, sodium (Na) reacts with chlorine (Cl2) to form sodium chloride (NaCl). The law of definite proportions ensures that the mass ratio of sodium to chlorine in sodium chloride will always be 1:1, regardless of the source of sodium and chlorine.

These examples demonstrate that chemical compounds have fixed mass ratios between their constituent elements, as dictated by the law of definite proportions. Regardless of the scale or source of the reactants, the proportions of elements in a compound remain constant.

Example Sum

Let’s consider the following chemical reaction:

2H2 + O2 -> 2H2O

In this reaction, hydrogen gas (H2) and oxygen gas (O2) combine to form water (H2O).

To prove the law of conservation of mass, we need to show that the total mass of the reactants is equal to the total mass of the products.

Step 1: Calculate the molar masses of each compound:

Molar mass of H2 = 2 grams/mole

Molar mass of O2 = 32 grams/mole

Molar mass of H2O = 18 grams/mole (2 hydrogen atoms with a molar mass of 1 each and 1 oxygen atom with a molar mass of 16)

Step 2: Calculate the total mass of the reactants:

Mass of 2 moles of H2 = 2 moles * 2 grams/mole = 4 grams

Mass of 1 mole of O2 = 1 mole * 32 grams/mole = 32 grams

Total mass of the reactants = 4 grams + 32 grams = 36 grams

Step 3: Calculate the total mass of the products:

Mass of 2 moles of H2O = 2 moles * 18 grams/mole = 36 grams

Total mass of the products = 36 grams

Step 4: Compare the total mass of the reactants and products:

The total mass of the reactants (36 grams) is equal to the total mass of the products (36 grams).

Therefore, this calculation demonstrates the law of conservation of mass, which states that mass is neither created nor destroyed in a chemical reaction. The total mass of the reactants is always equal to the total mass of the products.

Law of Multiple Proportions

The Law of Multiple Proportions states that when two elements combine to form different compounds, the ratio of masses of one element that combine with a fixed mass of the other element can be expressed in small whole numbers.

This law was first proposed by John Dalton and is an essential concept in understanding the atomic nature of matter.

Here are a few examples that illustrate this law with chemical equations:

Carbon Monoxide (CO) and Carbon Dioxide (CO2):

C + O2 → CO2

2C + O2 → 2CO

In these equations, carbon (C) reacts with oxygen (O2) to form carbon dioxide (CO2) and carbon monoxide (CO), respectively. The law of multiple proportions is evident here because the ratio of the masses of oxygen in the two compounds is 2:1, indicating that for a fixed mass of carbon, the masses of oxygen combine in small whole number ratios.

Nitric Oxide (NO) and Nitrogen Dioxide (NO2):

N2 + O2 → 2NO

2NO + O2 → 2NO2

In these equations, nitrogen (N2) reacts with oxygen (O2) to form nitric oxide (NO) and nitrogen dioxide (NO2), respectively. The law of multiple proportions is observed because the ratio of the masses of oxygen in the two compounds is 1:2, indicating that for a fixed mass of nitrogen, the masses of oxygen combine in small whole number ratios.

Hydrogen Peroxide (H2O2) and Water (H2O):

2H2 + O2 → 2H2O

2H2O2 → 2H2O + O2

These equations represent the formation of water (H2O) from the reaction of hydrogen gas (H2) and oxygen gas (O2) and the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2). The law of multiple proportions is evident because the ratio of the masses of oxygen in hydrogen peroxide and water is 2:1, indicating that for a fixed mass of hydrogen, the masses of oxygen combine in small whole number ratios.

These examples demonstrate the law of multiple proportions, which shows that when two elements combine to form different compounds, their masses combine in simple ratios, reflecting the ratios of small whole numbers.

Example Sum

Let’s consider the combination of carbon (C) and oxygen (O) to form two different compounds: carbon monoxide (CO) and carbon dioxide (CO2).

Step 1: Determine the molar masses of each element:

Molar mass of C = 12 grams/mole

Molar mass of O = 16 grams/mole

Step 2: Calculate the masses of oxygen in each compound:

Carbon monoxide (CO): Since there is one oxygen atom, the mass of oxygen = 1 * 16 grams = 16 grams.

Carbon dioxide (CO2): Since there are two oxygen atoms, the mass of oxygen = 2 * 16 grams = 32 grams.

Step 3: Compare the ratios of the masses of oxygen in each compound:

The ratio of the masses of oxygen in carbon monoxide to carbon dioxide is 16 grams : 32 grams, which can be simplified to 1 : 2.

This ratio can be expressed as a small whole number ratio (1:2). This demonstrates the law of multiple proportions because the masses of oxygen combine in different compounds in a simple, whole number ratio.

In summary, the law of multiple proportions states that when elements combine to form different compounds, the ratio of their masses can be expressed as small whole numbers. In the case of carbon and oxygen forming carbon monoxide and carbon dioxide, the mass ratio of oxygen is 1:2, demonstrating this law.

Law of Reciprocal Proportions

The law of reciprocal proportions, also known as Richter’s law, states that if two elements combine separately with a fixed amount of a third element, the ratio of the masses in which they combine will be either the same or a simple multiple of the ratio of their masses when they combine with each other.

Here’s an example to illustrate the law of reciprocal proportions:

Let’s consider the elements oxygen (O) and hydrogen (H) combining with chlorine (Cl) to form different compounds: hydrogen chloride (HCl) and water (H2O).

Step 1: Determine the molar masses of each element:

Molar mass of O = 16 grams/mole

Molar mass of H = 1 gram/mole

Molar mass of Cl = 35.5 grams/mole

Step 2: Calculate the masses of oxygen and hydrogen when combined with chlorine:

Hydrogen chloride (HCl): Since there is one hydrogen atom and one chlorine atom, the mass of hydrogen = 1 gram and the mass of chlorine = 35.5 grams.

Water (H2O): Since there are two hydrogen atoms and one oxygen atom, the mass of hydrogen = 2 grams and the mass of oxygen = 16 grams.

Step 3: Compare the ratios of the masses of oxygen and hydrogen when combined with chlorine:

The ratio of the masses of oxygen to hydrogen when combined with chlorine in HCl is 16 grams : 1 gram, which can be simplified to 16:1.

The ratio of the masses of oxygen to hydrogen when combined with chlorine in H2O is 16 grams : 2 grams, which can be simplified to 8:1.

Step 4: Examine the ratios of the masses of oxygen and hydrogen when combined with each other:

The ratio of the masses of oxygen to hydrogen when combined to form water (H2O) is 16 grams : 2 grams, which can be simplified to 8:1.

When we compare the ratios of the masses of oxygen and hydrogen in HCl and H2O, we find that the ratio of their masses in H2O (8:1) is a simple multiple (2 times) of the ratio in HCl (16:1).

This confirms the law of reciprocal proportions, which states that if two elements combine separately with a fixed amount of a third element, the ratio of their masses in which they combine will be either the same or a simple multiple of the ratio of their masses when they combine with each other. In this example, the ratio of oxygen to hydrogen in water (8:1) is a multiple of the ratio in hydrogen chloride (16:1).

Avogadro’s Law

Avogadro’s Law, formulated by Amedeo Avogadro, states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.

This law is crucial in understanding the relationship between the volume of a gas and the number of molecules it contains.

Avogadro’s Law is represented by the equation: V/n = k, where V is the volume, n is the number of moles, and k is a constant.

Here are a few examples that illustrate Avogadro’s law:

Equal volumes of different gases contain an equal number of molecules:

If we have a container with 1 liter of oxygen gas (O2) and another container with 1 liter of nitrogen gas (N2), both at the same temperature and pressure, Avogadro’s law states that they will contain the same number of molecules. This means that the number of molecules in 1 liter of oxygen gas will be the same as the number of molecules in 1 liter of nitrogen gas.

The effect of molar ratios on volume:

Avogadro’s law also applies to the molar ratios of gases in chemical reactions. For example, when hydrogen gas (H2) reacts with oxygen gas (O2) to form water vapor (H2O) according to the balanced equation:

2H2 + O2 → 2H2O

Avogadro’s law states that the volume of hydrogen gas required to react with a given volume of oxygen gas (at the same temperature and pressure) will be in a ratio of 2:1. This is because the ratio of the coefficients in the balanced equation reflects the molar ratio of the gases involved.

The relationship between volume and moles:

Avogadro’s law can also be applied to the relationship between volume and the number of moles of gas. For example, if we have a certain volume of carbon dioxide (CO2) gas and double the number of moles while keeping the temperature and pressure constant, Avogadro’s law states that the volume of the gas will also double. This means that the volume of gas is directly proportional to the number of moles when other factors are held constant.

These examples illustrate Avogadro’s law, which provides a fundamental understanding of the relationship between volume and the number of particles (moles) of gas at constant temperature and pressure.

Gay-Lussac’s Law of Combining Volumes

Gay-Lussac’s Law of Combining Volumes states that the volumes of gases involved in a chemical reaction, measured at the same temperature and pressure, are always in simple ratios.

These ratios correspond to the stoichiometric coefficients in the balanced chemical equation.

The pressure of a given amount of gas is directly proportional to its temperature when the volume is held constant.

Here are a few examples that demonstrate Gay-Lussac’s law:

Balloon experiment:

If you have a balloon filled with a fixed amount of gas at a certain temperature, and then you heat the balloon by placing it near a heat source, the temperature of the gas inside the balloon increases. According to Gay-Lussac’s law, as the temperature of the gas increases, the pressure inside the balloon also increases. This can be observed by the expansion of the balloon or by measuring the pressure using a pressure gauge.

Aerosol can:

Aerosol cans, such as those containing spray paint or deodorant, rely on Gay-Lussac’s law. The cans are pressurized with gas, and a liquid or solid substance is also present inside. When the valve is opened, the propellant gas escapes, causing a decrease in pressure inside the can. This decrease in pressure, combined with the constant temperature, leads to the liquid or solid substance being forced out of the can as a spray.

Scuba diving:

When scuba diving, divers carry compressed air tanks. The air inside the tank is pressurized to a level higher than the surrounding water pressure. According to Gay-Lussac’s law, as the temperature of the compressed air increases due to the surrounding water temperature, the pressure inside the tank also increases. This allows the diver to breathe the air at a pressure matching the water pressure, enabling them to explore underwater.

Here are a few more examples that illustrate Gay-Lussac’s law:

Hydrogen and Oxygen Reacting to Form Water:

2H2 + O2 → 2H2O

According to Gay-Lussac’s law, the volumes of hydrogen gas and oxygen gas consumed in this reaction will be in a ratio of 2:1. For example, if we have 2 liters of hydrogen gas, we would need 1 liter of oxygen gas to react completely to form 2 liters of water vapor.

Nitrogen and Hydrogen Reacting to Form Ammonia:

N2 + 3H2 → 2NH3

In this reaction, Gay-Lussac’s law states that the volumes of nitrogen gas and hydrogen gas consumed will be in a ratio of 1:3. If we have 2 liters of nitrogen gas, we would need 6 liters of hydrogen gas to react completely to form 4 liters of ammonia gas.

Carbon Monoxide and Oxygen Reacting to Form Carbon Dioxide:

2CO + O2 → 2CO2

According to Gay-Lussac’s law, the volumes of carbon monoxide gas and oxygen gas consumed in this reaction will be in a ratio of 2:1. If we have 2 liters of carbon monoxide gas, we would need 1 liter of oxygen gas to react completely to form 2 liters of carbon dioxide gas.

These examples demonstrate Gay-Lussac’s law, which establishes the relationship between the volumes of gases involved in a chemical reaction. The law states that the ratios of the volumes of reacting gases can be expressed as simple whole number ratios that correspond to the coefficients in the balanced chemical equation.

Dalton’s Atomic Theory

Dalton’s Atomic Theory is a fundamental concept that provides a framework for understanding the laws of chemical combinations.

According to Dalton, elements are made up of tiny, indivisible particles called atoms, which combine in fixed ratios to form compounds.

Atoms of different elements have different masses, and chemical reactions involve the rearrangement of atoms to form new substances.

Here are a few examples that illustrate Dalton’s atomic theory with chemical equations:

Formation of Water (H2O):

According to Dalton’s atomic theory, elements are made up of indivisible particles called atoms. In the case of water formation, the reaction can be represented as follows:

2H2 + O2 → 2H2O

This equation indicates that two molecules of hydrogen gas (H2) react with one molecule of oxygen gas (O2) to form two molecules of water (H2O). Dalton’s theory suggests that each hydrogen molecule consists of two hydrogen atoms (H), and each oxygen molecule consists of two oxygen atoms (O). Therefore, the reaction involves the rearrangement and combination of atoms to form new compounds.

Formation of Ammonia (NH3):

Dalton’s atomic theory also emphasizes that atoms combine in fixed ratios to form compounds. In the case of ammonia formation, the reaction can be represented as follows:

N2 + 3H2 → 2NH3

This equation indicates that one molecule of nitrogen gas (N2) reacts with three molecules of hydrogen gas (H2) to form two molecules of ammonia (NH3). Dalton’s theory suggests that each nitrogen molecule consists of two nitrogen atoms (N), and each hydrogen molecule consists of two hydrogen atoms (H). Therefore, the reaction involves the combination of atoms in fixed ratios to form the compound ammonia.

Decomposition of Water (H2O):

Dalton’s atomic theory also explains the process of chemical decomposition. For instance, the decomposition of water can be represented as follows:

2H2O → 2H2 + O2

This equation indicates that two molecules of water (H2O) can decompose into two molecules of hydrogen gas (H2) and one molecule of oxygen gas (O2). According to Dalton’s theory, this decomposition involves the separation of water molecules into their constituent atoms, with each water molecule consisting of two hydrogen atoms (H) and one oxygen atom (O).

These examples demonstrate how Dalton’s atomic theory provides a framework for understanding chemical reactions and the behavior of atoms in those reactions. The theory highlights the indivisibility of atoms and their role in combining and rearranging to form compounds or decompose into their constituent elements.

Conclusion

Understanding the laws of chemical combinations is crucial for grasping the foundations of chemistry. These laws, including the Law of Conservation of Mass, the Law of Definite Proportions, the Law of Multiple Proportions, Avogadro’s Law, and Gay-Lussac’s Law, provide the basis

Take Quiz

1. Which law states that the ratio of masses of elements in a compound is always constant?
(a) Avogadro’s law
(b) Dalton’s law
(c) Law of definite proportions
(d) Law of multiple proportions

ANSWER

c) Law of definite proportions

2. According to the law of multiple proportions, if two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element are in:
a) equal proportions
b) variable proportions
c) whole number ratios
d) fractional ratios

ANSWER

c) whole number ratios

3. The law of constant composition is also known as:
a) Dalton’s law
b) Boyle’s law
c) Gay-Lussac’s law
d) Proust’s law

ANSWER

d) Proust’s law

4. According to Avogadro’s law, equal volumes of gases at the same temperature and pressure contain:
a) equal numbers of molecules
b) equal masses of molecules
c) equal numbers of atoms
d) equal masses of atoms

ANSWER

a) equal numbers of molecules

5. The law of combining volumes of gases states that the ratio of volumes of gases involved in a chemical reaction can be expressed as small whole numbers. This is known as:
a) Boyle’s law
b) Charles’s law
c) Avogadro’s law
d) Gay-Lussac’s law

ANSWER

d) Gay-Lussac’s law

6. Which law states that the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of the individual gases?
a) Dalton’s law
b) Boyle’s law
c) Charles’s law
d) Avogadro’s law

ANSWER

a) Dalton’s law

7. The law of conservation of energy states that energy:
a) cannot be created or destroyed, only transformed
b) can be created but not destroyed
c) can be destroyed but not created
d) is irrelevant in chemical reactions

ANSWER

a) cannot be created or destroyed, only transformed

8. According to the law of definite proportions, the ratio of the masses of elements in a compound:
a) varies depending on the reaction conditions
b) is always a multiple of the smallest whole number ratio
c) is different for each reaction
d) is determined by the chemist conducting the experiment

ANSWER

b) is always a multiple of the smallest whole number ratio

9. The law of conservation of mass is not obeyed by a
a) Redox Reaction
b) Double Decomposition Reaction
c) Nuclear reaction
d) Neutralization Reaction

ANSWER

c) Nuclear reaction , since a nuclear reaction is not a chemical reaction

10. Two elements A and B combine chemically to form compounds I , II and III . The ratio of different masses of B combining with a fixed mass of A in I , II and III is 1:3:5 . If 32 parts of mass of A combine with 84 parts by mass of B in II , then in III , 16 parts of A will combine with __
a) 42 parts
b) 70 parts
c) 64 parts
d) 96 parts

ANSWER

b) 70 parts
In II, 32 parts by mass of A combine with 84 parts by mass od B . Thus 16 parts by mass of A (in II) will combine with 42 parts by mass of B . According to the data , different masses of B combining with a fixed mass of A in II and III are in the ratio 3 : 5
Mass of B in II / Mass of B in III = 3/5
Hence , mass of B in III = Mass of B in II X 5/3
= 42 X 5/3 = 70

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